如何替换 Python 中键的值？答案

【问题标题】：How do I replace the values of a key in Python?如何替换 Python 中键的值？
【发布时间】：2021-12-04 22:53:50
【问题描述】：

我有这个二十一点游戏，我正在尝试更改函数calculate_hand_value (hand) 并考虑到 Ace 的值可以是 1 而不是 11（如果总值超过 21，您希望 Ace计为 1)。谁能帮帮我？

import random

full_deck = {"Two of clubs": 2, "Three of clubs": 3, "Four of clubs": 4, "Five of clubs": 5, "Six of clubs": 6,
             "Seven of clubs": 7, "Eight of clubs": 8, "Nine of clubs": 9, "Ten of clubs": 10,
             "Jack of clubs": 10, "Queen of clubs": 10, "King of clubs": 10, "Ace of clubs": 11,
             "Two of diamonds": 2, "Three of diamonds": 3, "Four of diamonds": 4, "Five of diamonds": 5,
             "Six of diamonds": 6, "Seven of diamonds": 7, "Eight of diamonds": 8, "Nine of diamonds": 9,
             "Ten of diamonds": 10, "Jack of diamonds": 10, "Queen of diamonds": 10, "King of diamonds": 10,
             "Ace of diamonds": 11, "Two of hearts": 2, "Three of hearts": 3, "Four of hearts": 4, "Five of hearts": 5,
             "Six of hearts": 6,"Seven of hearts": 7, "Eight of hearts": 8, "Nine of hearts": 9, "Ten of hearts": 10,
             "Jack of hearts": 10, "Queen of hearts": 10, "King of hearts": 10, "Ace of hearts": 11,
             "Two of spades": 2, "Three of spades": 3, "Four of spades": 4, "Five of spades": 5, "Six of spades": 6,
             "Seven of spades": 7,  "Eight of spades": 8, "Nine of spades": 9, "Ten of spades": 10,
             "Jack of spades": 10, "Queen of spades": 10, "King of spades": 10, "Ace of spades": 11,
             }


def get_new_shuffled_deck():
    deck = list(full_deck.keys())
    random.shuffle(deck)
    return deck


def get_card_value(card):
    return full_deck[card]


def calculate_hand_value(hand):
    hand_value = 0

    for card in hand:
        hand_value += get_card_value(card)

    return hand_value

【问题讨论】：

标签： python function key blackjack

【解决方案1】：

for card in hand:
    hand_value += get_card_value(card)

    if hand_value > 21:
        hand_value -= 10

return hand_value

【讨论】：

这行不通，因为如果手牌中有 A，您只能减去 10。
我不玩黑杰克！对不起

【解决方案2】：

您可以为 ace 添加一个计数器，如果超过 21 个，您可以为每个 ace 减去 10 分。

def calculate_hand_value(hand):
    hand_value = 0
    aces = 0

    for card in hand:
        card_value = get_card_value(card)
        if card_value = 11:
            aces += 1
        hand_value += card_value

    for _ in range(aces):
        if hand_value > 21:
            hand_value -= 10

    return hand_value

【讨论】：

当我尝试你的代码时，我所有的卡值都是 0 :/
当我将它与@nadapez 的代码混合时，我让它工作了 :)
我刚刚修复了这个错误。很高兴您能够自己修复它。