【问题标题】:How to remove all cloned gui in roblox如何在 roblox 中删除所有克隆的 gui
【发布时间】:2021-04-16 04:07:50
【问题描述】:

我正在创建一个舞蹈表演游戏,我想在每一轮之前在列表中显示玩家的姓名和他们的顺序。我正在使用克隆,它为每个玩家创建一个新标签。我的问题是在第 1 轮之后克隆的列表没有被删除,并且玩家的名字是重复的。这是我的代码

contList.OnClientEvent:Connect(function(Contestants)  ---Remote event in local script
for i=1,#Contestants do
        nameList  = script.Parent.List.plrsList.nameList:Clone()
        nameList.Parent = script.Parent.List.plrsList
        nameList.Name = Contestants[i].Name    
        nameList.nList.Text = Contestants[i].Name     --players name
        seqNo = script.Parent.List.sequence.seqNo:Clone()
        seqNo.Parent = script.Parent.List.sequence
        seqNo.Name =i                                 --sequence number
        seqNo.sequence.Text = i
        List = script.Parent.List
    end
    List.Visible = true
    wait(10)
    List.Visible = false
    for i=1,#Contestants do
        nameList:Remove()
        seqNo:Remove()
    end
end)

【问题讨论】:

标签: for-loop oop lua clone roblox


【解决方案1】:

您的问题是,当您清理内容时,nameListseqno 变量仅指向您添加到列表中的最后一项,而不是删除您添加的所有项。

您可以通过几种不同的方法来删除它们,但我推荐的一种方法是

  1. 创建一个像框架一样的空容器。
  2. 创建新的 TextLabel 时,将其作为该 Frame 的子项。
  3. 当您准备好清理时,只需删除 Frame 即可立即删除所有子项。

看起来像这样:

contList.OnClientEvent:Connect(function(Contestants)  ---Remote event in local script
    -- find some UI elements
    local list = script.Parent.List
    local playersList = list.plrsList
    local playerNameList = playersList.nameList
    local sequence = list.sequence
    local sequenceNumber = sequence.seqNo

    -- 1. create an empty container for all players
    local container = Instance.new("Frame")
    container.Size = UDim2.new(1, 0, 1, 0)
    container.Position = UDim2.new(0, 0, 0, 0)
    container.BackgroundTransparency = 1.0
    local layout = Instance.new("UIListLayout", container)
    layout.SortOrder = Enum.SortOrder.Name

    -- 1a. create a container for player names
    local playerContainer = container:Clone()
    playerContainer.Parent = playersList

    -- 1b. create a container for player numbers
    local sequenceContainer = container:Clone()
    sequenceContainer.Parent = sequence

    -- 2. create an entry for every player, and put them into their containers
    for i = 1, #Contestants, 1 do
        local nameList  = playerNameList:Clone()
        nameList.Name = Contestants[i].Name
        nameList.nList.Text = Contestants[i].Name
        nameList.Parent = playerContainer

        local seqNo = sequenceNumber:Clone()
        seqNo.Name = tostring(i)
        seqNo.sequence.Text = tostring(i)
        seqNo.Parent = sequenceContainer
    end

    -- momentarily show the list
    list.Visible = true
    wait(10)
    list.Visible = false

    -- 3. clean up by deleting the containers
    playerContainer:Destroy()
    sequenceContainer:Destroy()
end)

【讨论】:

    猜你喜欢
    • 2012-12-20
    • 2020-09-25
    • 2021-09-18
    • 2022-07-13
    • 2020-11-01
    • 2015-12-31
    • 2019-10-30
    • 2012-05-07
    • 1970-01-01
    相关资源
    最近更新 更多