mysql试图按顺序排列行

Question

我想计算我的行的排序排名。它计算不正确 - 我只得到一个空值和 1。我希望根据我的连接/顺序按 ladder_name_lh2 = ladder_name_lh1 和 date_trigger_event_lh2 和 member_id_lh1 获得 1、2、3 的排名。

基本上，我想说的是 如果 ladder_name_2 与 ladder_name_1 匹配（这是设置之前/之后 - 阶梯 2 在阶梯 1 之后，并且有 6 个阶梯名称（类别），但为了说明它们是相关的，我想确保排名只有在匹配之前和之后的类别时才会生成），然后根据 date_2、member_id 生成排名。

我写了以下内容：

select 
        cte_ladder_history_self_join_lh1.member_id_lh1,
        cte_ladder_history_self_join_lh1.ladder_config_id_lh1,
        cte_ladder_history_self_join_lh1.trigger_name_lh1,
        cte_ladder_history_self_join_lh1.trigger_record_id_lh1,
        cte_ladder_history_self_join_lh1.date_trigger_event_lh1,
        cte_ladder_history_self_join_lh1.ladder_name_lh1,
        cte_ladder_history_self_join_lh1.ladder_value_lh1,
        cte_ladder_history_self_join_lh1.ladder_change_lh1,
        cte_ladder_history_self_join_lh2.member_id_lh2,
        cte_ladder_history_self_join_lh2.trigger_name_lh2,
        cte_ladder_history_self_join_lh2.trigger_record_id_lh2,
        cte_ladder_history_self_join_lh2.date_trigger_event_lh2,
        cte_ladder_history_self_join_lh2.ladder_name_lh2,
        cte_ladder_history_self_join_lh2.ladder_value_lh2,
        cte_ladder_history_self_join_lh2.ladder_change_lh2,
        datediff(cte_ladder_history_self_join_lh2.date_trigger_event_lh2,cte_ladder_history_self_join_lh1.date_trigger_event_lh1) as days_spent,
        @member_id:=member_id_lh2 AS member_id,
        @row_number:=(CASE
                WHEN @member_id = member_id_lh1
                THEN @row_number + 1
                ELSE 1
            END) AS rank 

    from 
        cte_ladder_history_self_join_lh1 #previous or current ladder history 
            left join cte_ladder_history_self_join_lh2 on cte_ladder_history_self_join_lh1.member_id_lh1 = cte_ladder_history_self_join_lh2.member_id_lh2
                and cte_ladder_history_self_join_lh2.ladder_name_lh2 = cte_ladder_history_self_join_lh1.ladder_name_lh1
                and cte_ladder_history_self_join_lh1.ladder_value_lh1 <> cte_ladder_history_self_join_lh2.ladder_value_lh2
                and cte_ladder_history_self_join_lh1.date_trigger_event_lh1 < cte_ladder_history_self_join_lh2.date_trigger_event_lh2 # lh2 shows second begin date / end date for lh if exists
        order by date_trigger_event_lh2 desc, member_id_lh1 desc; 

返回以下内容：

我不确定为什么排名不能正常工作。我希望排名在 1 到 20 之间（基于符合此人的 ladder_name = 倡导标准的行数），但我得到了一些截然不同的数字。

想法？

Answer 1

固定排名代码阅读：

CREATE TEMPORARY TABLE cte_leenk_ladder_history_rank
    SELECT * ,
    @row_number:=(CASE
    WHEN @member_id = member_id
    THEN @row_number + 1
    ELSE 1
    END) AS rank,
    @member_id := member_id

    FROM 
    cte_leenk_ladder_history_order
    where ladder_change = 1
    order by salesforce_id desc, date_trigger_event desc;