为什么这个简单的文本替换代码不起作用？

Question

在 *.docx 文件中使用这样的文本：

I scream.  You scream.  We all scream for ice cream.

I scream.You scream.We all scream for ice cream.

...（IOW，第一种情况下句子之间有两个空格，第二种情况下没有空格）我想在句子之间强制一个并且只有一个空格，所以它最终是这样的：

I scream. You scream. We all scream for ice cream.

I scream. You scream. We all scream for ice cream.

但是这段代码：

// 65..90 are A..Z; 97..122 are a..z
const int firstCapPos = 65;
const int lastCapPos = 90;
const int firstLowerPos = 97;
const int lastLowerPos = 122;

    . . .

// This will change sentences like this: "I scream.You scream.We all scream of ice cream." ...to this: "I scream. You scream. We all scream of ice cream."
private void SpacifySardinizedLetters(string filename)
{
    using (DocX document = DocX.Load(filename))
    {
        for (int i = firstCapPos; i <= lastCapPos; i++)
        {
            char c = (char)i;
            string originalStr = string.Format(".{0}", c);
            string newStr = string.Format(". {0}", c);
            document.ReplaceText(originalStr, newStr);
        }
        for (int i = firstLowerPos; i <= lastLowerPos; i++)
        {
            char c = (char)i;
            string originalStr = string.Format(".{0}", c);
            string newStr = string.Format(". {0}", c);
            document.ReplaceText(originalStr, newStr);
        }
        document.Save();
    }
}

// This will change sentences like this: "I scream.  You scream.  We all scream of ice cream." ...to this: "I scream. You scream. We all scream of ice cream."
private void SnuggifyLooseyGooseySentenceEndings(string filename)
{
    using (DocX document = DocX.Load(filename))
    {
        for (int i = firstCapPos; i <= lastCapPos; i++)
        {
            char c = (char)i;
            string originalStr = string.Format(".  {0}", c);
            string newStr = string.Format(". {0}", c);
            document.ReplaceText(originalStr, newStr);
        }
        for (int i = firstLowerPos; i <= lastLowerPos; i++)
        {
            char c = (char)i;
            string originalStr = string.Format(".  {0}", c);
            string newStr = string.Format(". {0}", c);
            document.ReplaceText(originalStr, newStr);
        }
        document.Save();
    }
}

...仅适用于紧缩在一起的句子-它们之间有两个空格的句子无法更改。为什么？我的代码或 docx 库中是否存在错误？

Answer 1

你可以用正则表达式来代替：

using System.Text.RegularExpression;

string text = readFromDocx();
string newText = Regex.Replace( text, @"\.[^\S\n]*(\w)",
    m => string.Format( ". {0}", m.Groups[ 1 ] ) )

双重否定旨在匹配除换行符之外的所有空格，通常包含在\s 说明符中。

Answer 2

我按照我在comment 中所说的做了，下载了DocX，创建了一个 Microsoft Word 文档并从引用 DocX 库的项目中运行了这段代码：

// Contains "Foo.Bar and Foo.  Bar"
string filename = "TestWordDocument.docx";

using (DocX document = DocX.Load(filename))
{
    document.ReplaceText(".B", ". B");
    document.ReplaceText(".  B", ". B");
    document.Save();
})

还有Word文件，之前包含：

Foo.Bar and Foo.  Bar

之后包含：

Foo. Bar and Foo. Bar

所以，对我有用。

编辑：我在包含您问题的第一行的文件上运行了您的代码，并且它有效。您确定您正在运行此代码并且正在查看正确的文件吗？

Answer 3

试试这个 docX.Replace() 代码，很容易将文本从某个文本更改为另一个文本。

static void Replace(string filename, string a, string b)
    {
        using (DocX document = DocX.Load(filename))
        {
            document.ReplaceText(a, b);

            document.Save();
        } 
    }