【发布时间】:2017-03-22 13:06:09
【问题描述】:
我在 php 中有以下代码用于连接到我的数据库:
<?php
class MY_SQL{
private $username;
private $password;
private $conn;
public function __construct($SERVERNAME){
$this->username = "username";
$this->password = "password";
if($SERVERNAME == "data_"){
$server = "Servername";
}
else {
$server = $SERVERNAME;
}
// Create connection
$conn = new mysqli($server, $this->username, $this->password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
}
public function SQLCommand($cmd) {
if ( $this->conn->query($cmd) === TRUE ) {
echo "New record created successfully";
} else {
echo "Error: " . $cmd . "<br>" . $conn->error;
}
}
}
$sql = "INSERT INTO _test(test1, test2) VALUES ('hello','hi');";
$database = new MY_SQL("Servername");
$database->SQLCommand($sql);
?>
我收到以下错误:
致命错误:在 null 上调用成员函数 query()
出了什么问题?
【问题讨论】:
-
忘记选择数据库!!!
-
@Saty 你是对的!
标签: php mysql null call member