我该如何处理 SyntaxError: Unexpected token: Typo [关闭]

Question

我想知道我的错误的逻辑以及我应该如何编写它，请。谢谢你

这是问题：

编写一个名为“findShortestOfThreeWords”的函数。 给定 3 个字符串，“findShortestOfThreeWords”返回给定字符串中最短的一个。 如果有关系，它应该返回参数列表中的第一个单词。

我得到的错误：

/home/runner/Module-1/index.js:21 }esle{ ^ SyntaxError：意外的令牌'{'

我的代码：

function findShortestOfThreeWords(word1, word2, word3){
  //if word1 was less than or equal word2
    //return word1
  //else
    //return word2
  //if word1 is less than or equal word3
    //return word1
  //esle 
    //return word3
  //if word2 is less than or equal word3
    //return word2
  //else
    //return word3

if(word1.length <= word2.length){
  return word1;
}else{
  return word2;
}if(word1.length <= word3.length){
  return word1;
}esle{
  return word3;
}if(word2.length <= word3.length ){
  return word2;
}else{
  return word3;
}
  
}

var output = findShortestOfThreeWords('a', 'two', 'three');
console.log(output); // --> 'a'

Answer 1

将esle 更改为else

function findShortestOfThreeWords(word1, word2, word3){
  //if word1 was less than or equal word2
    //return word1
  //else
    //return word2
  //if word1 is less than or equal word3
    //return word1
  //esle 
    //return word3
  //if word2 is less than or equal word3
    //return word2
  //else
    //return word3

if(word1.length <= word2.length){
  return word1;
}else{
  return word2;
}if(word1.length <= word3.length){
  return word1;
}else{
  return word3;
}if(word2.length <= word3.length ){
  return word2;
}else{
  return word3;
}
  
}

var output = findShortestOfThreeWords('a', 'two', 'three');
console.log(output); // --> 'a'

Answer 2

您的代码中似乎有一个错字： esle{ 返回 word3;

尝试将其更改为 else