【发布时间】:2019-02-22 16:35:53
【问题描述】:
我正在用 C++ 编写一个 websocket 服务器,但无法让握手工作。 Chrome 报告错误是由于接受标头错误,但我相信该值是正确的。
作为一个示例交换,客户端发送以下密钥:
Sec-WebSocket-Key: ypX0m2zum/pt80mxlVo8PA==
我的服务器发回:
Sec-WebSocket-Accept: Kl4mnqm5QA6bBmGf3EAN0nyGXws=
我已经根据 RFC 中的示例测试了我的服务器,并且它检查出来了。我不知道为什么它不被接受。我的理论是,我一定是在做其他事情,它会产生与错误接受值相同的错误。
这是来自wireshark捕获的不同请求:
Hypertext Transfer Protocol
GET /websocket HTTP/1.1\r\n
Host: 127.0.0.1:8443\r\n
Connection: Upgrade\r\n
Pragma: no-cache\r\n
Cache-Control: no-cache\r\n
User-Agent: Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.109 Safari/537.36\r\n
Upgrade: websocket\r\n
Origin: chrome-extension://eajaahbjpnhghjcdaclbkeamlkepinbl\r\n
Sec-WebSocket-Version: 13\r\n
Accept-Encoding: gzip, deflate, br\r\n
Accept-Language: en-US,en;q=0.9\r\n
Sec-WebSocket-Key: +zJ3/KI/Zrumgh+AjxopRQ==\r\n
Sec-WebSocket-Extensions: permessage-deflate; client_max_window_bits\r\n
\r\n
[Full request URI: http://127.0.0.1:8443/websocket]
[HTTP request 1/1]
[Response in frame: 6]
下面是回复:
Hypertext Transfer Protocol
HTTP/1.1 101 Switching Protocols\r\n
Upgrade: websocket\r\n
Connection: Upgrade\r\n
Sec-WebSocket-Accept: anTEIFyI/gTepr8Q3okBj81M2/4=\r\n
\r\n
[HTTP response 1/1]
[Time since request: 0.000245010 seconds]
[Request in frame: 4]
有人能告诉我回复有什么问题吗?我的接受值不正确吗?
编辑 1:
我用来创建响应值的代码。 websocket_key 是从之前的请求中获取的。
const char *magic_string = "258EAFA5-E914-47DA-95CA-C5AB0DC85B11";
int pre_hash_size = 36 + websocket_key.size();
char pre_hash[pre_hash_size];
memcpy(pre_hash, websocket_key.c_str(), websocket_key.size());
memcpy(pre_hash + websocket_key.size(), magic_string, 36);
unique_ptr<Botan::HashFunction> hash1(Botan::HashFunction::create("SHA-1"));
Botan::secure_vector<uint8_t> post_hash = hash1->process(reinterpret_cast<const uint8_t *>(pre_hash), pre_hash_size);
string accept_response = base64_encode(post_hash.data(), post_hash.size());
这是base 64函数:
/*
base64.cpp and base64.h
base64 encoding and decoding with C++.
Version: 1.01.00
Copyright (C) 2004-2017 René Nyffenegger
This source code is provided 'as-is', without any express or implied
warranty. In no event will the author be held liable for any damages
arising from the use of this software.
Permission is granted to anyone to use this software for any purpose,
including commercial applications, and to alter it and redistribute it
freely, subject to the following restrictions:
1. The origin of this source code must not be misrepresented; you must not
claim that you wrote the original source code. If you use this source code
in a product, an acknowledgment in the product documentation would be
appreciated but is not required.
2. Altered source versions must be plainly marked as such, and must not be
misrepresented as being the original source code.
3. This notice may not be removed or altered from any source distribution.
René Nyffenegger rene.nyffenegger@adp-gmbh.ch
*/
static const std::string base64_chars =
"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"abcdefghijklmnopqrstuvwxyz"
"0123456789+/";
std::string base64_encode(unsigned char const *bytes_to_encode, unsigned int in_len)
{
std::string ret;
int i = 0;
int j = 0;
unsigned char char_array_3[3];
unsigned char char_array_4[4];
while (in_len--)
{
char_array_3[i++] = *(bytes_to_encode++);
if (i == 3)
{
char_array_4[0] = (char_array_3[0] & 0xfc) >> 2;
char_array_4[1] = ((char_array_3[0] & 0x03) << 4) + ((char_array_3[1] & 0xf0) >> 4);
char_array_4[2] = ((char_array_3[1] & 0x0f) << 2) + ((char_array_3[2] & 0xc0) >> 6);
char_array_4[3] = char_array_3[2] & 0x3f;
for (i = 0; (i < 4); i++)
ret += base64_chars[char_array_4[i]];
i = 0;
}
}
if (i)
{
for (j = i; j < 3; j++)
char_array_3[j] = '\0';
char_array_4[0] = (char_array_3[0] & 0xfc) >> 2;
char_array_4[1] = ((char_array_3[0] & 0x03) << 4) + ((char_array_3[1] & 0xf0) >> 4);
char_array_4[2] = ((char_array_3[1] & 0x0f) << 2) + ((char_array_3[2] & 0xc0) >> 6);
for (j = 0; (j < i + 1); j++)
ret += base64_chars[char_array_4[j]];
while ((i++ < 3))
ret += '=';
}
return ret;
}
【问题讨论】:
-
你能不能也显示你用来生成值的代码?
-
@Ferrybig 编辑已添加。
标签: websocket