【发布时间】:2018-06-18 04:58:49
【问题描述】:
我在停靠小部件中有一个可编辑的列表视图。我想跟踪用户编辑之前的数据和用户编辑之后的数据。完整的相关代码是:
void MainWindow :: createDock()
{
//initialize dockWidget
QDockWidget *dock = new QDockWidget("Tags", this);
dock->setAllowedAreas(Qt::LeftDockWidgetArea | Qt::RightDockWidgetArea);
dock->setFeatures(QDockWidget::DockWidgetFloatable | QDockWidget::DockWidgetMovable);
//widget to store all widgets placed inside dock because dock cannot set layout but can set widget
QWidget *tags = new QWidget(dock);
//initiazlize treeViewModel
listViewModel = new QSqlTableModel(this);
listViewModel->setTable("tags");
listViewModel->select();
listViewModel->setHeaderData(0, Qt::Horizontal, "Tags");
//set the model for treeView
listView = new QListView(dock);
listView->setModel(listViewModel);
connect(listView, &QListView::doubleClicked, this, &MainWindow::onListViewDoubleClicked, Qt::UniqueConnection);
connect(listViewModel, &QSqlTableModel::dataChanged, this, &MainWindow::onLVDataChanged, Qt::UniqueConnection);
//add treeView to the dock
QVBoxLayout *layout = new QVBoxLayout;
layout->addWidget(listView);
tags->setLayout(layout);
//add the dock widget to the main window and show it
dock->setWidget(tags);
this->addDockWidget(Qt::LeftDockWidgetArea, dock);
//dock->show();
}
void MainWindow :: onLVDataChanged(const QModelIndex& index, const QModelIndex& index2, const QVector<int> & roles)
{
QMetaMethod metaMethod = sender()->metaObject()->method(senderSignalIndex());
QMessageBox::information(this, "", metaMethod.name());
afterUpdate = index.data().toString();
//do somethings
beforeUpdate = "";
afterUpdate = "";
}
void MainWindow :: onListViewDoubleClicked(const QModelIndex &index)
{
QMetaMethod metaMethod = sender()->metaObject()->method(senderSignalIndex());
QMessageBox::information(this, "", metaMethod.name());
beforeUpdate = index.data().toString();
}
我这样做: 我双击一个项目以对其进行编辑。 onDoubleClick() 只被调用一次(见于 QMessageBox)。我在现有数据中添加了一个空格(在我的情况下是“小说”,我将其更改为“小说”)。但是,在我按下回车后,dataChanged() 被调用了两次(再次通过 QMessageBox 看到)。
我没有明确发出信号。它仅由模型发出。
【问题讨论】:
-
你检查过信号发送的角色了吗?
void QAbstractItemModel::dataChanged(const QModelIndex &topLeft, const QModelIndex &bottomRight, const QVector<int> &roles = ...) -
现在? @eyllanesc
-
你做了什么动作来触发信号?请改进您的示例并提供一个不错的 MCVE
-
问题出在 onListViewDoubleClicked 还是 onLVDataChanged?
标签: c++ qt qt5 qlistview qsqltablemodel