javascript innerhtml 不会将变量发送到链接答案

【问题标题】：javascript innerhtml won't send a variable to a linkjavascript innerhtml 不会将变量发送到链接
【发布时间】：2015-11-06 05:51:33
【问题描述】：

我正在使用 ajax 开发 laravel 我将数据发送到服务器并获取用户然后我不会编辑视图并删除用户我正在使用 javascript innerhtml 为用户创建一个表，但是当我为编辑视图创建链接并删除它时，它重定向但不发送数据，而是将变量作为链接发送。

这是我的ajax

<script>
function getstudent(str) {
    var xmlhttp;
    var dep = document.getElementById("department").value;

    if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp = new XMLHttpRequest();
    } else { // code for IE6, IE5
        xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
    }

    xmlhttp.onreadystatechange = function () {
        if (xmlhttp.readyState == 4) {

            var data = xmlhttp.responseText;
            var obj = JSON.parse(data);
            var x = obj.length;
            var j;

            var table = document.getElementById("myTable");
            var head = document.getElementById("head");
            // table.innerHTML="<tbody> </tbody>"
            head.innerHTML = " <tr> <th>identification</th><th>first name</th><th>last name</th> <th>gfname</th> </tr>"
            //document.getElementById("mytable").innerHTML=' ';
            table.appendChild(head);

            for (j = 0; j <= x; j++) {

                var row = table.insertRow(j + 1);

                // Insert new cells (<td> elements) at the 1st and 2nd position of the "new" <tr> element:
                var cell1 = row.insertCell(0);
                var cell2 = row.insertCell(1);
                var cell3 = row.insertCell(2);
                var cell4 = row.insertCell(3);
                var cell5 = row.insertCell(4);
                var cell6 = row.insertCell(5);
                var cell7 = row.insertCell(6);
                // Add some text to the new cells:
                cell1.innerHTML = obj[j].identification;
                cell2.innerHTML = obj[j].name;
                cell3.innerHTML = obj[j].fname;
                cell4.innerHTML = obj[j].gfname;
                var user = obj[j].id;
                cell5.innerHTML = "<a href='{{ action("
                UserController@show "," + user + ") }}' class='btn btn-default'>View</a>&emsp;";
                cell6.innerHTML = "<a href='{{ action("
                UserController@edit "," + user + ") }}' class='btn btn-default'>View</a>&emsp;";
                cell5.innerHTML = "<a href='{{ action("
                UserController@destroy "," + user + ") }}' class='btn btn-default'>View</a>&emsp;";

            }
        }
    }

    xmlhttp.open("GET", "indexstudget/" + str + "/" + dep, true);
    xmlhttp.send('');
}

这是我的一些观点

<div class="form-group">
    <label class="col-md-4 control-label">Department</label>
    <div class="col-md-6">
        <select id='department' class="form-control" name="department" onchange="year(this.value)">
            <option>select</option>@foreach( $departments as $department)
            <option name="department" value={{ $department->id }}> {{$department->name}}</option>@endforeach</select>
    </div>
</div>
<br>
<br>
<div class="form-group">
    <label class="col-md-4 control-label">Year</label>
    <div class="col-md-6">
        <select id='demo' name='demo' class="form-control" onchange="getstudent(this.value)">
            <option>select</option>
        </select>
    </div>
</div>@if ( $students->isEmpty() ) There are no students. @else
<table class="table table-striped" id="myTable">
    <thead id="head"></thead>
</table>@endif
<div class="panel-body"> <a href="{{ action('RegistrarController@create') }}" class="btn btn-primary">Create user</a>

    </form>
</div>
</div>

它使用正确的用户列表创建表，但是当我单击它时它发送变量而不是数据

喜欢这个

网址http://project/edituser/+user+

【问题讨论】：

标签： javascript php jquery ajax laravel

【解决方案1】：

我将控制器操作更改为直接路由并且它起作用了。像这样

"<a href='{{ action("UserController@show","+user+") }}' class='btn btn-default'>View</a>&emsp;"
"<a href='showuser/"+user+"' class='btn btn-default'>View</a>&emsp;"

【讨论】：