【发布时间】:2022-01-04 09:44:42
【问题描述】:
我正在尝试通过文件系统中的 UNIX 套接字让 gunicorn 在 Apache 代理后面运行。长话短说,它在非强制模式下与 SELinux 一起工作,但在强制模式下不工作。我正在努力解决这个问题。这是我由 gunicorn 创建的套接字文件:
srwxrwxrwx. dh dh system_u:object_r:httpd_sys_content_t:s0 /var/www/wsgi/dham_wsgi.sock
在通过 Apache 访问失败后,audit2why 对此有何评论:
type=AVC msg=audit(1641287516.397:870181): avc: denied { connectto } for pid=23897 comm="httpd" path="/var/www/wsgi/dham_wsgi.sock" scontext=system_u:system_r:httpd_t:s0 tcontext=system_u:system_r:init_t:s0 tclass=unix_stream_socket permissive=0
Was caused by:
Missing type enforcement (TE) allow rule.
You can use audit2allow to generate a loadable module to allow this access.
让我们按照这个提示,阅读一些手册页和互联网,然后开始工作:
$ sudo cat /var/log/audit/audit.log | audit2allow -m httpd_socket -l > httpd_socket.te
$ cat httpd_socket.te
module httpd_socket 1.0;
require {
type httpd_t;
type httpd_sys_content_t;
class sock_file write;
}
#============= httpd_t ==============
allow httpd_t httpd_sys_content_t:sock_file write;
$ checkmodule -M -m -o httpd_socket.mod httpd_socket.te
checkmodule: loading policy configuration from httpd_socket.te
checkmodule: policy configuration loaded
checkmodule: writing binary representation (version 19) to httpd_socket.mod
$ semodule_package -o httpd_socket.pp -m httpd_socket.mod
$ sudo semodule -i httpd_socket.pp
但它不起作用,一切都和以前一样。重新启动 Apache 没有任何区别。现在呢?
【问题讨论】: