从 Snap To Road API 获取结果答案

【问题标题】：Get Results From Snap To Road API从 Snap To Road API 获取结果
【发布时间】：2016-09-14 06:07:19
【问题描述】：

需要帮助。所以我正在使用 Google API Snap To Road。这是我的代码：

<?php
set_time_limit(0);
$jsonarr = array();
$today=date("Y-m-d");

$ACCOUNT=$_GET['ACCOUNT'];
$ticket_no=$_GET['ticket_no'];
require_once("config/msdb_connect.php");

$query = mssql_query("SELECT * FROM TblGps WHERE DOOR = '".$ticket_no."' AND     DATETIME BETWEEN '".$today." 00:00:00' AND '".$today." 23:59:59' ORDER BY DATETIME DESC");
while($row = mssql_fetch_array($query))
{
  //parameters
  $lng=$row['LONG'];
  $lat=$row['LAT'];
  //$data = array('lat'=>$lat,'lng'=>$lng);
  //echo $latlng = GetArray($data);

$jsonarr[] = array(
                        'id' => $row['ID'],
                      'account' => $row['ACCOUNT'],
                      'datetime' =>date("m/d/Y     H:i:s",strtotime($row['DATETIME'])),
                      'loc' => $row['LOCATION'],
                      // 'speed' => $row['SPEED'],
                      'longi' => $lng,
                      'lat' => $lat,
                      'lac' => $row['LAC'],
                      'cid' => $row['CID'],
                      // 'engine' => $row['ENGINE'],
                      'remarks' => $row['REMARKS']
                      );
}

$path = GetArray($jsonarr);
$snailtrail=GetSnailTrail($path);

function GetArray($array){

  $stringdata = "";
  for($i = 0 ; $i <= count($array) - 1 ; $i++){
    $rows = (object)$array[$i];
    if($i == count($array) - 1) $stringdata .= $rows->lat.','.$rows->longi;
    else $stringdata .= $rows->lat.','.$rows->longi.'|';
  }
  return $stringdata;
 }
function GetSnailTrail($path){
    $key='AIzaSyDRlfacNyHn7ZOsC0FzufqZ_rtQYfZD6wA';
    $url='https://roads.googleapis.com/v1/snapToRoads?path='.$path.'&interpolate=true&key='.$key.' ';

    $curl = curl_init();
    curl_setopt($curl, CURLOPT_URL, $url);
    curl_setopt($curl, CURLOPT_CUSTOMREQUEST,"POST");
    // curl_setopt($curl, CURLOPT_POSTFIELDS, $json);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, false);
    curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);

     $api_response = curl_exec($curl);
    curl_close($curl);
    $result = json_decode($api_response);

    $result = (object)$result;
    $result = (object)$result->location;

    return $result;
  }

所以我从我的数据库中获取经度和纬度。然后，我将使用我的函数 GetArray 将其组合为 GetSnailTrail 函数中参数路径的多条记录。

所以在发送 API 之前会是这样：

https://roads.googleapis.com/v1/snapToRoads?path=14.567467,121.030726|14.566950,121.030497|14.567447,121.031204|14.566947,121.030520|14.566947,121.030520|14.567590,121.031181|14.567590,121.031181|14.567377,121.031236|14.566947,121.030520|14.567447,121.031204|14.566947,121.030520|14.566947,121.030520|14.566947,121.030520|14.566947,121.030520|14.567590,121.031181|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567590,121.031181|14.567377,121.031236|14.567590,121.031181|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567466,121.030726|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567056,121.030569|14.567012,121.030539|14.567049,121.030568|14.567009,121.030545|14.567468,121.030728|14.567031,121.030549|14.567007,121.030545|14.567098,121.030403|14.567037,121.030548|14.567178,121.030624|14.566899,121.030486|14.566946,121.030520|14.567056,121.030569|14.567056,121.030569|14.567056,121.030569|14.566946,121.030520|14.566947,121.030522|14.566947,121.030522|14.566947,121.030522|14.567103,121.030594|14.566946,121.030520|14.566947,121.030522|14.566947,121.030524|14.567028,121.030556|14.566780,121.030502|14.566780,121.030502|14.567103,121.030594|14.567103,121.030594|14.566947,121.030522|14.566946,121.030520|14.566946,121.030520|14.566946,121.030520|14.566947,121.030524|14.566947,121.030524&interpolate=true&key=AIzaSyDRlfacNyHn7ZOsC0FzufqZ_rtQYfZD6wA

之后，API 将返回如下结果：

{
  "snappedPoints": [
    {
      "location": {
        "latitude": 14.567361300000002,
        "longitude": 121.03068420000001
      },
      "originalIndex": 0,
      "placeId": "ChIJF6oagKzJlzMRlFWOLr4F1SI"
}

由于某种原因，我无法在我的$jsonarr 上回显或获得将其输入的响应。收到回复后怎么办？谢谢

【问题讨论】：

curl 是否提供了任何错误？参考：curl_error。和var_dump($api_response)。
是的，它显示 411 错误

标签： php google-api google-api-php-client

【解决方案1】：

鉴于它在浏览器中返回的 url 和相关数据，以访问返回数据的每个部分，我发现这工作正常，假设 $data 被分配了来自 curl 请求的响应。

curl 请求是使用 GET 而不是 POST 完成的，并且响应在函数外部解码。以前您的代码试图访问$result->location ~ 而它应该是$result->snappedPoints

    function GetSnailTrail( $path=false ){
        if( !$path )return false;
        $key='AIzaSyDRlfacNyHn7ZOsC0FzufqZ_rtQYfZD6wA';
        $url='https://roads.googleapis.com/v1/snapToRoads?path='.$path.'&interpolate=true&key='.$key.' ';

        $curl = curl_init();
        curl_setopt($curl, CURLOPT_URL, $url);
        curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, false);
        curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);

        $result = curl_exec($curl);
        curl_close($curl);

        return $result;
    }

    $path='14.567467,121.030726|14.566950,121.030497|14.567447,121.031204|14.566947,121.030520|14.566947,121.030520|14.567590,121.031181|14.567590,121.031181|14.567377,121.031236|14.566947,121.030520|14.567447,121.031204|14.566947,121.030520|14.566947,121.030520|14.566947,121.030520|14.566947,121.030520|14.567590,121.031181|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567590,121.031181|14.567377,121.031236|14.567590,121.031181|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567466,121.030726|14.567377,121.031236|14.567377,121.031236|14.567377,121.031236|14.567447,121.031204|14.567377,121.031236|14.567056,121.030569|14.567012,121.030539|14.567049,121.030568|14.567009,121.030545|14.567468,121.030728|14.567031,121.030549|14.567007,121.030545|14.567098,121.030403|14.567037,121.030548|14.567178,121.030624|14.566899,121.030486|14.566946,121.030520|14.567056,121.030569|14.567056,121.030569|14.567056,121.030569|14.566946,121.030520|14.566947,121.030522|14.566947,121.030522|14.566947,121.030522|14.567103,121.030594|14.566946,121.030520|14.566947,121.030522|14.566947,121.030524|14.567028,121.030556|14.566780,121.030502|14.566780,121.030502|14.567103,121.030594|14.567103,121.030594|14.566947,121.030522|14.566946,121.030520|14.566946,121.030520|14.566946,121.030520|14.566947,121.030524|14.566947,121.030524';

    $data=GetSnailTrail( $path );

    if( $data ) {

        $json=json_decode( $data,true );
        $points=$json['snappedPoints'];

        foreach( $points as $key => $value ){
            $obj=(object)$value;
            $lat=$obj->location['latitude'];
            $lng=$obj->location['longitude'];
            $index=property_exists($obj,'originalIndex') ? $obj->originalIndex : 'n/a';
            $id=$obj->placeId;
            echo 'id:'.$id.' index:'.$index.' lat:'.$lat.' lng:'.$lng.'<br />';
        }
    }

最初构建路径时，您可以进一步简化代码。如果您要在 while 循环中构造一个数组并使用 lat/lng 填充，而不是一个复杂的函数来处理 $jsonarr 数据，如下所示：

$pathdata=array();

while( $row = mssql_fetch_array( $query ) ){
    $jsonarr[] = array(
        'id'        =>  $row['ID'],
        'account'   =>  $row['ACCOUNT'],
        'datetime'  =>  date( "m/d/Y H:i:s", strtotime( $row['DATETIME'] ) ),
        'loc'       =>  $row['LOCATION'],
        'longi'     =>  $row['LONG'],
        'lat'       =>  $row['LAT'],
        'lac'       =>  $row['LAC'],
        'cid'       =>  $row['CID'],
        'remarks'   =>  $row['REMARKS']
    );
    $pathdata[]="{$row['LAT']},{$row['LONG']}";
}

$path=implode('|',$pathdata);

然后你可以implode使用选择的分隔符（|）来实现点的字符串。

要使用 javascript 处理此问题，您可以使用以下内容：

echo "
<script type='text/javascript'>
    /* \$data is already a json object, echo it in javascript and process */
    var path={$data};

    function processpath( path ){
        var json=path.snappedPoints;
        for( var o in json ){
            try{
                var point=json[ o ];
                if( typeof( point )!='undefined' ){

                    var lat=point.hasOwnProperty('location') && point.location.hasOwnProperty('latitude') ? point.location.latitude : false;
                    var lng=point.hasOwnProperty('location') && point.location.hasOwnProperty('longitude') ? point.location.longitude : false;
                    var index=point.hasOwnProperty('originalIndex') ? point.originalIndex : 'n/a';
                    var id=point.hasOwnProperty('placeId') ? point.placeId : 'n/a';

                    if( lat && lng ) console.log( 'id:%s, index:%s, lat:%s, lng:%s', id, index, lat, lng );
                }
            }catch( err ){
                console.warn( err );
                continue;
            }
        }
    }
    processpath( path );
</script>";

【讨论】：

感谢您的回答。请问如何去掉“BR”？
哦，对不起 - BR 是一个本地定义的常量 - 我在发布答案时总是忘记删除它......它是 <br />
谢谢...但是我怎样才能把它放在 $jsonarray 上，这将由我的 javascript 显示？而不是数据库中的 long lat？
没有提到 javascript。您可以通过将响应回显为 javascript 变量而不是在 php 中处理来处理 javascript 中的整个响应。你能澄清一下你的意思以及你将在哪里使用 javascript 吗？