【问题标题】:c pointer to pointer memory allocationc 指向指针内存分配的指针
【发布时间】:2010-11-25 01:06:35
【问题描述】:

我是 c 中的菜鸟,我的这段代码不能正常工作,因为我为 char** 指针做了一些糟糕的内存分配。能否请你帮忙?提前很多。 代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>



struct node_t {

 struct tuple_t *tuple; //Entrada na lista

 struct node_t *next; //o node seguinte da lista

};

struct tuple_t {
 long timestamp; /* instante de criacao do tuplo*/
 int n_fields; /* numero de campos deste tuplo */
 char **fields; /* array com campos do tuplo */
 /* 4 + 4 + 4  bytes?? */
};

char ** split_str(char [], char **, const char *);

struct node_t *node_create(void *node_data){

 struct node_t *node = NULL;
 node = (struct node_t *)malloc(sizeof(struct node_t));
 if(!node){
  printf("Erro ao criar um node!\n");
  return NULL;
 }

 node->tuple = (struct tuple_t *)malloc(sizeof(struct tuple_t));
 if(!node->tuple){printf("Erro ao criar o node->tuple\n"); free(node); return NULL;}

 node->tuple->fields = (char ** )malloc(strlen((char *) node_data) * sizeof(char *));
 if(!node->tuple->fields){ printf("Erro ao criar o node->tuple->node_fields\n"); free(node->tuple); free(node); return NULL; }

 char **array;
 const char *sep=" ";
 char *s = (char *)node_data;
 char arr[strlen(s)];
 int i = 0;
 while(arr[i++]=s[i]);

 array = split_str(arr,array, sep); 

 i = 0;
 while(array[i]){
  node->tuple->fields[i] = (char *)malloc((strlen(array[i])) * sizeof(char));
  if(!node->tuple->fields[i]){
   printf("Erro ao alocar memoria em node_create() para node->tuple->fields[i]\n");
   return NULL;
  }
  node->tuple->fields[i] = array[i];
//  printf("array[i]=%s\n",array[i]);
//  printf("node->tuple->fields[i]=%s\n",node->tuple->fields[i]);
  i++;

 }

 node->tuple->n_fields = i;
 node->tuple->timestamp = 0L;
 node->next = NULL;

 return node;
}

char** split_str(char writablestring[],char **array, const char *sep ){

 array = malloc(strlen(writablestring) + 1);

 if(! array){printf("Erro ao alocar memoria para o array em split\n"); return NULL;}

 char *token = strtok(writablestring, sep);

 int i=0;
 while(token != NULL)
 {
  array[i] = malloc(strlen(token)+1);
  if(!array[i])
   return NULL;
  array[i] = token;
  token = strtok(NULL, " ");
  i++;
 }

 return array;
}


int main(int argc, char** argv)
{

 void * n_data = "hello 123 ploc";

 struct node_t * node = node_create(n_data);
 printf("node->num_fields=%d\n", node->tuple->n_fields);
 int i=0;

 while( node->tuple->fields[i] ){
  printf("node->tuple->fields[%d]=%s\n",i,node->tuple->fields[i]);
  i++;
 }

 return 0;
}

结束代码。

【问题讨论】:

  • 我看到了一些粗略的东西。例如,将node_data 作为void * 传递,为node-&gt;tuple-&gt;fields[i] 分配内存然后立即覆盖它(也许您的意思是memcpystrcpy),以及内存泄漏。但这将有助于解释您尝试在整体上以及在每个部分中做什么。
  • 对不起,我没有时间回答...基本上,我想在 tuple_t 结构的“字段”字段中添加拆分的字符串。但你是对的,代码很乱。幸运的是,现在我有一个解决方案;)

标签: c memory allocation


【解决方案1】:

您的split_str() 函数返回指向writablestring 的指针,即node_create() 中的数组arr。然后将这些指针复制到node-&gt;tuple-&gt;fields[i] - 但arr 数组在node_create() 函数退出后将不存在 - 因此这些指针将不再有效。相反,您需要将返回的字符串 复制 到您分配的内存中(这也显示了如何使用 for() 循环代替 while(),您还需要释放split_str()中分配的内存):

for (i = 0; array[i]; i++) {
    node->tuple->fields[i] = malloc(strlen(array[i]) + 1);

    if (!node->tuple->fields[i]){
        printf("Erro ao alocar memoria em node_create() para node->tuple->fields[i]\n");
        return NULL;
    }

    strcpy(node->tuple->fields[i], array[i]);
}

free(array);

此外,您的代码假定split_str() 返回的数组将由NULL 终止,但该函数不能确保这一点。该函数还有许多其他问题(传递给malloc() 的大小不正确,由不必要的malloc() 引起的内存泄漏) - 所以你也需要修复它:

char **split_str(char writablestring[], const char *sep)
{
    char **array = malloc(strlen(writablestring) * sizeof array[0]);

    if(!array) {
        printf("Erro ao alocar memoria para o array em split\n");
        return NULL;
    }

    char *token = strtok(writablestring, sep);
    int i;

    for (i = 0; (array[i] = token) != NULL; i++) {
        token = strtok(NULL, " ");
    }

    return array;
}

(请注意,array 不需要作为参数传递 - 无论如何它都会立即被覆盖,所以我将它变成了一个局部变量)。


完成此操作后,您可能会注意到实际上没有理由在split_str() 中分配array,只需将其内容复制到node-&gt;tuple-&gt;fields 然后释放它。您不妨将数组node-&gt;tuple-&gt;fields 传递给split_str() 并将其直接写入其中。然后它可以返回分配的字符串数量 - 这看起来像:

int split_str(char [], char **, const char *);

struct node_t *node_create(void *node_data)
{
    struct node_t *node = NULL;
    char *s = node_data;
    size_t slen = strlen(s);

    node = malloc(sizeof *node);
    if (!node) {
        printf("Erro ao criar um node!\n");
        return NULL;
    }

    node->tuple = malloc(sizeof *node->tuple);
    if (!node->tuple) {
        printf("Erro ao criar o node->tuple\n");
        free(node);
        return NULL;
    }

    node->tuple->fields = malloc(slen * sizeof node->tuple->fields[0]);
    if (!node->tuple->fields) {
        printf("Erro ao criar o node->tuple->node_fields\n");
        free(node->tuple);
        free(node);
        return NULL;
    }

    char arr[slen + 1];
    strcpy(arr, s);

    int i = split_str(arr, node->tuple->fields, " ");

    node->tuple->n_fields = i;
    node->tuple->timestamp = 0L;
    node->next = NULL;

    return node;
}

int split_str(char writablestring[], char **array, const char *sep)
{
    char *token = strtok(writablestring, sep);
    int i;

    for (i = 0; token != NULL; i++) {
        array[i] = malloc(strlen(token) + 1);
        if (!array[i]) {
            printf("Erro ao criar o array[i]\n");
            break;
        }
        strcpy(array[i], token);
        token = strtok(NULL, " ");
    }

    return i;
}

【讨论】:

    【解决方案2】:

    试试这样的方法:

    #include <stdio.h> 
    #include <stdlib.h> 
    #include <string.h> 
    
    
    struct tuple_t
    { 
        long timestamp; /* instante de criacao do tuplo*/ 
        int n_fields; /* numero de campos deste tuplo */ 
        char** fields; /* array com campos do tuplo */ 
    }; 
    
    struct node_t
    { 
        struct tuple_t* tuple; //Entrada na lista 
        struct node_t* next; //o node seguinte da lista 
    }; 
    
    
    char** split_str(const char *, const char *, int *); 
    void node_destroy(struct node_t*);
    
    struct node_t* node_create(char* node_data)
    { 
        struct node_t* node = (struct node_t *) malloc(sizeof(struct node_t)); 
        if(!node)
        { 
            printf("Erro ao criar um node!\n"); 
            return NULL; 
        } 
    
        node->tuple = (struct tuple_t *) malloc(sizeof(struct tuple_t));
        if(!node->tuple)
        {
            printf("Erro ao criar o node->tuple\n");
            node_destroy(node);
            return NULL;
        } 
    
        node->tuple->timestamp = 0L; 
    
        node->tuple->fields = split_str(node_data, " ", &(node->tuple->n_fields));
        if(!node->tuple->fields)
        {
            printf("Erro ao criar o node->tuple->node_fields\n");
            node_destroy(node);
            return NULL;
        } 
    
        node->next = NULL; 
    
        return node; 
    } 
    
    void node_destroy(struct node_t* node)
    {
        if(node)
        {
            if(node->tuple)
            {
                if(node->tuple->fields)
                {
                    for(int i = 0; i < node->tuple->n_fields; ++i)
                        free(node->tuple->fields[i]);
    
                    free(node->tuple->fields);
                }
    
                free(node->tuple);
            }
    
            free(node);
        }
    }
    
    char** split_str(const char* str, const char* sep, int* found)
    { 
        if (found) *found = 0;
    
        int len = strlen(str);
    
        char** array = (char**) malloc(len * sizeof(char*));
        if(!array)
        {
            printf("Erro ao alocar memoria para o array em split\n");
            return NULL;
        }
    
        ++len;
    
        char* writablestring = (char*) malloc(len); 
        if(!array)
        {
            printf("Erro ao alocar memoria para writeablestring em split\n");
            free(array);
            return -1;
        } 
    
        strncpy(writablestring, str, len);
    
        char* token = strtok(writablestring, sep); 
        int i = 0;
    
        while(token)
        { 
            len = strlen(token) + 1;
    
            array[i] = (char*) malloc(len);
            if(!array[i]) 
            {
                printf("Erro ao alocar memoria para o array item em split\n");
    
                free(writeablestring);
                for(int j = 0; j < i; ++j)
                    free(array[j]);
                free(array);
                return NULL;
            }
    
            strncpy(array[i], token, len); 
            ++i;
    
            token = strtok(NULL, sep);
        } 
    
        free(writeablestring);
    
        if(found) *found = i;
        return array; 
    } 
    
    
    int main(int argc, char** argv) 
    { 
        char* n_data = "hello 123 ploc"; 
    
        struct node_t* node = node_create(n_data); 
        if(node)
        {
            printf("node->tuple->n_fields=%d\n", node->tuple->n_fields);
    
            for(int i = 0; i < node->tuple->n_fields; ++i)
                printf("node->tuple->fields[%d]=%s\n", i, node->tuple->fields[i]);
    
            node_destroy(node);
        }
    
        return 0; 
    } 
    

    【讨论】:

    • 老兄!很多人......与这个相比,我的代码真的很糟糕......又好又流畅。
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