【问题标题】:Fill Sparse Data with SQL (Rockset)用 SQL 填充稀疏数据(Rockset)
【发布时间】:2021-12-11 22:42:10
【问题描述】:

我们创建了以下查询,以便将稀疏时间序列数据转换为具有特定时隙的密集数据。这个想法是将时间范围(例如 1 小时)转换为不同的时隙(例如 60 x 1 分钟时隙)。对于每个槽(在本例中为 1 分钟),我们计算是否有一个或多个值,如果有,我们使用 MAX 函数来获取我们的值。如果时间范围内没有值,我们将使用前一个时隙中的值。

这是基本查询:

WITH readings AS (
  (
    -- Get the first value before the time window to set the entry value
    SELECT
      timestamp AS timestamps,
      attributeId AS id,
      DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) AS ts,
      value AS value
    FROM
      node_iot_attribute_values
    WHERE
      attributeId = 'cu937803-ne9de7df-nn7453b2-na2c7e14'
      AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) < TIMESTAMP '2021-10-26T08:42:06.000000Z'
    ORDER BY
      ts DESC
    LIMIT
      1
  )
  UNION
    (
      -- Get the values in the time range
      SELECT
        timestamp AS timestamps,
        attributeId AS id,
        DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) AS ts,
        value AS value
      FROM
        node_iot_attribute_values
      WHERE
        attributeId = 'cu937803-ne9de7df-nn7453b2-na2c7e14'
        AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) > TIMESTAMP '2021-10-26T08:42:06.000000Z'
        AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) < TIMESTAMP '2021-10-26T09:42:06.000000Z'
    )
),
slots AS (
  -- Create time slots at the correct resolution
  SELECT
    TIMESTAMP '2021-10-26T08:42:06.000000Z' + MINUTES(u.i - 1) AS last_ts,
    TIMESTAMP '2021-10-26T08:42:06.000000Z' + MINUTES(u.i) AS ts
  FROM
    UNNEST(SEQUENCE(0, 60, 1) AS i) AS u
),
slot_values AS (
  -- Get the values for each time slot from the readings retrieved
  SELECT
    slots.ts,
    (
      SELECT
        r.value
      FROM
        readings r
      WHERE
        r.ts <= slots.ts
      ORDER BY
        r.ts DESC
      LIMIT
        1
    ) AS last_val,
    (
      SELECT
        MAX(r.value)
      FROM
        readings r
      WHERE
        r.ts <= slots.ts
        AND r.ts >= slots.last_ts
    ) AS slot_agg_val,
  FROM
    slots
)
SELECT
  -- Use either the MAX value if several are in the same slot or the last if none
  CAST(ts AT TIME ZONE 'Europe/Paris' AS string) AS ts,
  COALESCE(
    slot_agg_val,
    LAG(slot_agg_val, 1) OVER(
      ORDER BY
        ts
    ),
    last_val
  ) AS value
FROM
  slot_values
ORDER BY
  ts;

好消息是查询有效。坏消息是性能很糟糕!!!

有趣的是,从存储中检索数据的查询部分非常高效。在我们的例子中,这部分查询在 ~50ms 内返回所有结果

WITH readings AS (
  (
    -- Get the first value before the time window to set the entry value
    SELECT
      timestamp AS timestamps,
      attributeId AS id,
      DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) AS ts,
      value AS value
    FROM
      node_iot_attribute_values
    WHERE
      attributeId = 'cu937803-ne9de7df-nn7453b2-na2c7e14'
      AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) < TIMESTAMP '2021-10-26T08:42:06.000000Z'
    ORDER BY
      ts DESC
    LIMIT
      1
  )
  UNION
    (
      -- Get the values in the time range
      SELECT
        timestamp AS timestamps,
        attributeId AS id,
        DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) AS ts,
        value AS value
      FROM
        node_iot_attribute_values
      WHERE
        attributeId = 'cu937803-ne9de7df-nn7453b2-na2c7e14'
        AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) > TIMESTAMP '2021-10-26T08:42:06.000000Z'
        AND DATE_TRUNC('second', TIMESTAMP_SECONDS(timestamp)) < TIMESTAMP '2021-10-26T09:42:06.000000Z'
    )
)

分析了查询的不同部分后,性能爆炸式增长的是:

slot_values AS (
  -- Get the values for each time slot from the readings retrieved
  SELECT
    slots.ts,
    (
      SELECT
        r.value
      FROM
        readings r
      WHERE
        r.ts <= slots.ts
      ORDER BY
        r.ts DESC
      LIMIT
        1
    ) AS last_val,
    (
      SELECT
        MAX(r.value)
      FROM
        readings r
      WHERE
        r.ts <= slots.ts
        AND r.ts >= slots.last_ts
    ) AS slot_agg_val,
  FROM
    slots
)

由于某种原因,这部分需要大约 25 秒才能执行!非常感谢您在优化此查询方面提供的帮助。

【问题讨论】:

    标签: sql time-series rockset


    【解决方案1】:

    我会使用 JOIN 和 AGGREGATION 逻辑来计算它。 SQL 适用于 map 和 reduce 逻辑。

    试试

    SELECT
        filled_slots.ts,
        MAX(value) AS last_val,
        slot_agg_val
      FROM
        (
          SELECT
            slots.ts,
            MAX(previous_r.ts) last_previous_time,
            MAX(in_interval_r.value) AS slot_agg_val,
          FROM
            slots
            LEFT JOIN readings previous_r ON previous_r.ts <= slots.ts
            LEFT JOIN readings in_interval_r ON in_interval_r.ts < slots.ts
            AND in_interval_r.ts > slots.last_ts
          GROUP BY
            slots.ts
        ) filled_slots
        LEFT JOIN readings ON filled_slots.last_previous_time = readings.ts
      GROUP BY
        filled_slots.ts,
        slot_agg_val
    

    最后一个聚合有助于避免由于重复数据引起的问题。 代码未经测试。

    【讨论】:

    • 在 ts,value 2021-10-26T10:42:06,-7.0 2021-10-26T10:43:06,-6.6 2021-10-26T10:44:06,-7.1 而新代码:ts,value 2021-10-26T10:42:06, 2021-10-26T10:43:06,-6.6 2021-10-26T10:44:06,-7.1 最初的 -7.0 似乎丢失了。
    • 正确检查查询后,用于获取`last_val`的逻辑无法正常工作。因此缺少值。
    • 哎呀,左连接应该在 last_previous_time ofc ... LEFT JOIN readings ON filled_slots.last_previous_time = readings.ts 如果它按预期工作,我编辑我的答案
    • 轰隆隆!!!!令人惊叹的工作(尤其是在无法访问数据的情况下)!
    猜你喜欢
    • 1970-01-01
    • 2021-09-23
    • 2022-01-17
    • 2012-07-28
    • 2023-04-05
    • 1970-01-01
    • 1970-01-01
    • 1970-01-01
    • 2012-11-02
    相关资源
    最近更新 更多