【发布时间】：2013-07-08 17:26:50
【问题描述】：
我有一个应用程序正在尝试调用一项服务，而另一项服务似乎正在超时。问题是我的应用程序没有收到任何超时异常，尽管我确实看到控制台打印出错误：
[13年7月8日12：39：32：360 EDT] 00000005 TimeoutManage我WTRN0006W：事务0000013FBF252E43000000010000000CE81CB4935851D5C13DECD3DBB2D463F0DBECAEE60000013FBF252E43000000010000000CE81CB4935851D5C13DECD3DBB2D463F0DBECAEE600000001已120秒后的超时。 [7/8/13 12:39:32:360 EDT] 00000005 TimeoutManage I WTRN0124I：当超时发生时，与事务关联或最近关联的线程是 Thread[WebContainer : 1,5,main]。发生超时时该线程的堆栈跟踪是： java.lang.Object.wait（本机方法） java.lang.Object.wait(Object.java:196) com.ibm.io.async.AbstractAsyncFuture.waitForCompletion（AbstractAsyncFuture.java:334） com.ibm.io.async.AsyncFuture.getByteCount(AsyncFuture.java:218) com.ibm.ws.tcp.channel.impl.AioSocketIOChannel.readAIOSync(AioSocketIOChannel.java:215) com.ibm.ws.tcp.channel.impl.AioTCPReadRequestContextImpl.processSyncReadRequest(AioTCPReadRequestContextImpl.java:182) com.ibm.ws.tcp.channel.impl.TCPReadRequestContextImpl.read(TCPReadRequestContextImpl.java:111) com.ibm.ws.http.channel.outbound.impl.HttpOutboundServiceContextImpl.parseResponseMessageSync(HttpOutboundServiceContextImpl.java:1657) com.ibm.ws.http.channel.outbound.impl.HttpOutboundServiceContextImpl.readSyncResponse(HttpOutboundServiceContextImpl.java:725) com.ibm.ws.http.channel.outbound.impl.HttpOutboundServiceContextImpl.startResponseReadSync(HttpOutboundServiceContextImpl.java:1775) com.ibm.ws.http.channel.outbound.impl.HttpOutboundServiceContextImpl.finishRequestMessage(HttpOutboundServiceContextImpl.java:1195) com.ibm.ws.websvcs.transport.http.out.HttpOutSyncWriter.finishBufferRequest(HttpOutSyncWriter.java:94) com.ibm.ws.websvcs.transport.http.out.HttpOutWriter.writeBuffer(HttpOutWriter.java:136) com.ibm.ws.websvcs.transport.http.out.HttpOutByteBufferOutputStream.finish(HttpOutByteBufferOutputStream.java:468) com.ibm.ws.websvcs.transport.http.SOAPOverHTTPSender.sendChunkedRequest(SOAPOverHTTPSender.java:890) com.ibm.ws.websvcs.transport.http.SOAPOverHTTPSender.sendSOAPRequest(SOAPOverHTTPSender.java:807) com.ibm.ws.websvcs.transport.http.SOAPOverHTTPSender.send(SOAPOverHTTPSender.java:611) com.ibm.ws.websvcs.transport.http.HTTPTransportSender.invoke(HTTPTransportSender.java:364) org.apache.axis2.engine.AxisEngine.send(AxisEngine.java:531) org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOperation.java:401) org.apache.axis2.description.OutInAxisOperationClient.executeImpl(OutInAxisOperation.java:228) org.apache.axis2.client.OperationClient.execute(OperationClient.java:163) org.apache.axis2.jaxws.core.controller.impl.AxisInvocationController.execute(AxisInvocationController.java:581) org.apache.axis2.jaxws.core.controller.impl.AxisInvocationController.doInvoke(AxisInvocationController.java:130) org.apache.axis2.jaxws.core.controller.impl.InvocationControllerImpl.invoke(InvocationControllerImpl.java:93) org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invokeSEIMethod(JAXWSProxyHandler.java:364) org.apache.axis2.jaxws.client.proxy.JAXWSProxyHandler.invoke(JAXWSProxyHandler.java:185)使用以下设置创建客户端：
bindProvider.getRequestContext().put(com.ibm.wsspi.webservices.Constants.RESPONSE_TIMEOUT_PROPERTY , connectionProperties.getProperty(MyService.TIME_OUT));
bindProvider.getRequestContext().put(com.ibm.wsspi.webservices.Constants.CONNECTION_TIMEOUT_PROPERTY , connectionProperties.getProperty(MyService.TIME_OUT));
bindProvider.getRequestContext().put(com.ibm.wsspi.webservices.Constants.READ_TIMEOUT_PROPERTY , connectionProperties.getProperty(MyService.TIME_OUT));
MyService.TIME_OUT 的值为 20000，我已验证它设置正确。
捕获调用服务的代码如下所示：
try
{
response = ((MyServicePortType) myService).doWebServiceOperation(request);
}
catch (Throwable e) //I know, catch Throwable is not very good but right now I'd be happy to catch ANYthing here!
{
log.error("Webservice reported error",e);
}
即使我更改了catch 块以捕获任何东西，我仍然没有捕获任何异常。 WebSphere 检测到事务超时，但我不知道为什么应用程序没有检测到 Web 服务调用中的超时。我是否遗漏了什么会导致引发适当的超时异常，以便我可以捕获它并将消息发送到应用程序框架？
【问题讨论】：
标签： java web-services