将链接值传递给 bean

Question

我有一个带有如下链接的 JSP 文件：

<a href="links.do?method=homeAdmin">
<a href="links.do?method=signUp">

我有一个动作类LinkAction.java：

public class LinkAction extends org.apache.struts.action.Action {

    public ActionForward signUp(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        return mapping.findForward("signUp");
    }
    public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        return mapping.findForward("homeAdmin");
    }
}

问题是它不起作用。但是当我把它改成这样的时候，它只适用于signUp 动作。

public class LinkAction extends org.apache.struts.action.Action {

    @Override
    public ActionForward execute(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        return mapping.findForward("signUp");
    }

}

我也试过改成

public class LinkAction extends DispatchAction { ... }

这是我的struts-config.xml

<action input="/index.jsp"
        name="signUp" 
        path="/links" 
        scope="session" 
        type="Actions.LinkAction">
   <forward name="signUp" path="/signUp.jsp"/>
   <forward name="homeAdmin" path="/homeAdmin.jsp"/>
</action>

我想对我网页中的所有链接使用这个单一的操作文件。我该怎么做？

Answer 1

您需要添加parameter="method"。这标识了包含方法名称的请求参数。

如果你有下一个动作类：

package actions;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;

public class LinkAction extends DispatchAction {

    public ActionForward signUp(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        return mapping.findForward("signUp");
    }

    public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        return mapping.findForward("homeAdmin");
    }
}

您将需要在struts-config.xml 文件中进行以下配置：

<form-beans>
    <form-bean name="SignUpForm" type="org.apache.struts.action.DynaActionForm">
        <form-property name="fname" type="java.lang.String" />
        <form-property name="lname" type="java.lang.String" />
        <form-property name="usr" type="java.lang.String" />
        <form-property name="pwd" type="java.lang.String" />
    </form-bean>
</form-beans>
<action-mappings>
    <action path="/links"
            type="actions.LinkAction"
            name="SignUpForm"
            input="/index.jsp"
            parameter="method"
            scope="session">
       <forward name="signUp" path="/signUp.jsp"/>
       <forward name="homeAdmin" path="/homeAdmin.jsp"/>
    </action>
</action-mappings>

另见org.apache.struts.actions.DispatchAction。

Answer 2

Struts1 always calls execute(ActionMapping mapping, ActionForm form,
        HttpServletRequest request, HttpServletResponse response) 

处理请求的方法。您可以尝试在execute() 方法中获取请求parameter('method') 并根据其值将其代理给homeAdmin 或signUp。

Answer 3

正如上面 piyush 解释的那样，通过 DispatchAction click http://struts.apache.org/release/1.3.x/struts-extras/apidocs/org/apache/struts/actions/DispatchAction.html 扩展你的动作类来做到这一点

你的配置文件中的配置应该是这样的

<action-mappings>
  <action input="/yourpage.jsp" parameter="method" name="yourform" 
    path="/yourAction" scope="session/request" type="yourpackage.youraction">
    <forward name="signup" path="/yourpage.jsp" />
</action>

Answer 4

根据我的问题，

1.) 有没有什么办法，通过一个动作类，你可以处理多项任务，比如：你的两种方法都可以工作。

public ActionForward signUp(ActionMapping mapping, ActionForm form,
    HttpServletRequest request, HttpServletResponse response)
    throws Exception {

return mapping.findForward("signUp");
}

public ActionForward homeAdmin(ActionMapping mapping, ActionForm form,
    HttpServletRequest request, HttpServletResponse response)
    throws Exception {

return mapping.findForward("homeAdmin");
}

如果正确，那么您应该选择另一种类型的 Action，即 DispatchAction，因为它提供了编写多个方法的能力。

详情：

public class LanguageSelectAction extends DispatchAction{

public ActionForward chinese(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {

    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.SIMPLIFIED_CHINESE);

    return mapping.findForward("provide");
}

public ActionForward english(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {

    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.ENGLISH);

    return mapping.findForward("success");
}

public ActionForward german(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {

    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.GERMAN);

    return mapping.findForward("success");
}

public ActionForward france(ActionMapping mapping,ActionForm form,
    HttpServletRequest request,HttpServletResponse response) 
throws Exception {

    request.getSession().setAttribute(
            Globals.LOCALE_KEY, Locale.FRANCE);

    return mapping.findForward("success");
}

}

你可以得到详细的here