SAS 过程报告

Question

我有以下数据集（虚构数据）：

data have;
    input team $ goals_12 goals_13 var_12_13;
cards;
LIV 20 25 .25
MNC 21 24 .14
MUN 30 25 -.17
ARS 10 12 .20
CHE 23 23 0
EVE 20 18 -.1
TOT 10 0 -1
;
run;

我正在尝试为此数据集创建报告。这是我所拥有的：

proc report data=have;
    column team goals_12 goals_13 var_12_13;
    define team / 'Team';
    define goals_12 / analysis '2012 Goals';
    define goals_13 / analysis '2013 Goals';
    define var_12_13 / order analysis format=percent. mean "Variance '12 to '13";
    rbreak after / summarize ul ol;
run;

这几乎做了我想要的一切。以下是我无法弄清楚的事情：

1. 将摘要行命名为“摘要”
2. 按 var_12_13 降序排列，因此方差最大的团队排在第一位
3. 我需要将方差列的摘要作为总计的方差，而不是方差的平均值（因此应该是 -5%）

Answer 1

试试这个：

proc sort data=work.have; by descending var_12_13;

proc report data=have;
    column team goals_12 goals_13 var_12_13;
    define team / 'Team';
    define goals_12 / analysis '2012 Goals';
    define goals_13 / analysis '2013 Goals';
    define var_12_13 / order=data analysis format=percent. mean "Variance '12 to '13" weight=goals_13;

    compute team;
    if _BREAK_ in ('_RBREAK_') 
        then do;
            team="Summary";
        end;
    endcomp;

    rbreak after / summarize ul ol;
run;