【发布时间】：2021-09-07 07:13:00
【问题描述】：
我正在编写一个小程序：
- 获取一个excel文件
- 从该 excel 文件中读取一些潜在的文件名
- 搜索潜在文件名是该名称一部分的文件
我的问题是：我有两列带有复选按钮。但出于某些原因，column1 (cb) 中的复选按钮绑定到 column2 (cb2) 中的复选按钮。因此，当在 column1 或 column2 中按下一个复选按钮时，另一列中相应的复选按钮会被选中或取消选中。
import tkinter as tk
from tkinter import filedialog
import pandas as pd
import numpy as np
import os
class FileMover:
def __init__(self):
self.master = tk.Tk()
self.master.title('File Mover')
self.master.geometry('700x700')
self.master.resizable(0,0)
self.source_folder_path = ''
self.destination_folder_path = ''
self.part_dict = {}
self.mainframe = tk.Frame(self.master, height=700, width=700, highlightbackground='red', highlightthickness=0)
self.mainframe.grid(row=0, column=0)
self.mainframe.grid_propagate(False)
self.top_frame = tk.Frame(self.mainframe, height=84, width=700, highlightbackground='blue', highlightthickness=3)
self.top_frame.grid(row=0, column=0)
self.top_frame.grid_propagate(False)
self.center_frame = tk.Frame(self.mainframe, height=700-2*80-2*3, width=700, highlightbackground='red', highlightthickness=0)
self.center_frame.grid(row=1, column=0)
self.center_frame.grid_propagate(False)
self.botton_frame = tk.Frame(self.mainframe, height=80, width=700, highlightbackground='red', highlightthickness=3)
self.botton_frame.grid(row=2, column=0, sticky='s')
self.botton_frame.grid_propagate(False)
self.left_frame = tk.Frame(self.center_frame, height=700-2*80, width=350, highlightbackground='blue', highlightthickness=3)
self.left_frame.grid(row=0, column=0)
self.left_frame.grid_propagate(False)
self.right_frame = tk.Frame(self.center_frame, height=700-2*80, width=350, highlightbackground='green', highlightthickness=3)
self.right_frame.grid(row=0, column=1)
self.right_frame.grid_propagate(False)
self.b_get_part_list = tk.Button(self.top_frame, text='Select Part List', width=20, command=self.get_file_names).grid(row=0, column=0, sticky='w')
self.b_get_source_folder = tk.Button(self.top_frame, text='Select Source Folder', width=20, command=self.get_source_folder).grid(row=1, column=0, sticky='w')
self.b_get_destination_folder = tk.Button(self.top_frame, text='Select Destination Folder', width=20, command=self.get_destination_folder).grid(row=2, column=0, sticky='w')
self.left_scroller = tk.Scrollbar(self.left_frame)
self.left_scroller.grid(row=0, column=1, sticky='ns')
self.left_text =tk.Text(self.left_frame, width=40, height=33)
self.left_text.grid(row=0, column=0)
self.left_text.config(yscrollcommand=self.left_scroller.set)
self.left_scroller.config(command=self.left_text.yview)
self.right_scroller = tk.Scrollbar(self.right_frame)
self.right_scroller.grid(row=0, column=1, sticky='ns')
self.right_text = tk.Text(self.right_frame, width=40, height=33)
self.right_text.grid(row=0, column=0)
self.right_text.config(yscrollcommand=self.right_scroller.set)
self.right_scroller.config(command=self.right_text.yview)
def get_file_names(self):
excel_file_path = filedialog.askopenfilename(title='Select Part List', filetypes=[('Excel Files', '*.xlsx')])
l1 = tk.Label(self.top_frame, text=f'{excel_file_path}')
l1.grid(row=0, column=1, sticky='w')
df = pd.read_excel(excel_file_path)
col_A = 'Unnamed: 0'
col_B = 'Unnamed: 1'
index_start = 16
index_end = len(df[col_A])
for index in range(index_start, index_end, 1):
if (df.iloc[index][col_A] and df.iloc[index][col_B]) not in self.part_dict:
if not np.isnan(df.iloc[index][col_A]):
self.part_dict[str(df.iloc[index][col_A])] = {}
self.part_dict[str(df.iloc[index][col_A])]['variable_cb'] = tk.IntVar()
else:
self.part_dict[str(df.iloc[index][col_B])] = {}
self.part_dict[str(df.iloc[index][col_B])]['variable_cb'] = tk.IntVar()
self.cb_packer()
def cb_packer(self):
for index, key in enumerate(self.part_dict):
cb = tk.Checkbutton(self.left_frame, text=key, bg='white', command=lambda i=index: self.cb_changer(list(self.part_dict)[i]))
self.left_text.window_create('end', window=cb)
self.left_text.insert('end', '\n')
def cb_changer(self, name):
if self.part_dict[name]['variable_cb'].get() != 1:
self.part_dict[name]['variable_cb'].set(1)
print(self.part_dict[name]['variable_cb'].get())
else:
self.part_dict[name]['variable_cb'].set(0)
print(self.part_dict[name]['variable_cb'].get())
def cb2_packer(self):
for index, key in enumerate(self.part_dict):
try:
cb2 = tk.Checkbutton(self.right_frame, text=self.part_dict[key]['file'], bg='white', command=lambda i=index: self.cb2_changer(list(self.part_dict)[i]))
self.right_text.window_create('end', window=cb2)
self.right_text.insert('end', '\n')
except:
pass
def cb2_changer(self, name):
if self.part_dict[name]['variable_cb2'].get() != 1:
self.part_dict[name]['variable_cb2'].set(1)
print(self.part_dict[name]['variable_cb2'].get())
else:
self.part_dict[name]['variable_cb2'].set(0)
print(self.part_dict[name]['variable_cb2'].get())
def get_source_folder(self):
self.source_folder_path = filedialog.askdirectory(title='Select Source Folder')
l2 = tk.Label(self.top_frame, text=f'{self.source_folder_path}')
l2.grid(row=1, column=1, sticky='w')
self.file_crawler()
self.cb2_packer()
def file_crawler(self):
for path, subdirs, files in os.walk(self.source_folder_path):
for file in files:
for key in self.part_dict:
if key in file:
try:
self.part_dict[key]['file']
except:
if file.endswith('pdf') or file.endswith('PDF') or file.endswith('dxf') or file.endswith('DXF') or file.endswith('stp') or file.endswith('STP') or file.endswith('step') or file.endswith('STEP'):
self.part_dict[key]['path'] = path
self.part_dict[key]['file'] = file
self.part_dict[key]['variable_cb2'] = tk.IntVar()
def get_destination_folder(self):
pass
gui = FileMover()
gui.master.mainloop()
【问题讨论】：
-
我认为使用
.csv文件会更好：它们更容易阅读，因为它们是原始文本。此外，您可以将 excel 文件导出到.csv。 -
我不是生成 xlsx 文件的人。我的问题是，当检查或取消检查其他列中的核心禁止核般的托管顿时，还是未选中。 span>
-
好的，我知道，我只是想告诉你这个选项。这样您就可以避免因使用模块读取文件的方式而产生的错误。
-
您发布的代码太多了。你能把它剪成minimal reproducible example吗？
-
我不能 100% 确定我的代码的哪些部分导致了错误。我敢打赌，它位于以下函数之一中：cb_packer、cb2_packer、cb_changer 或 cb2_changer。
标签： variables tkinter python-3.8