【发布时间】:2018-01-02 17:00:05
【问题描述】:
嗨,我正在研究这段代码:
#include <signal.h>
#include <stdio.h>
#include <string.h>
#include <sys/time.h>
#include <unistd.h>
#include <stdlib.h>
#include <stdbool.h>
volatile sig_atomic_t print_flag = true;
static int count = 0;
void timer_handler (int signum)
{
printf ("timer expired %d times\n", ++count);
if(count>20) {
print_flag = false;
}
}
int main ()
{
struct sigaction sa;
struct itimerval timer;
/* Install timer_handler as the signal handler for SIGVTALRM. */
memset (&sa, 0, sizeof (sa));
sa.sa_handler = &timer_handler;
sigaction (SIGALRM, &sa, NULL);
/* Configure the timer to expire after 250 msec... */
timer.it_value.tv_sec = 0;
timer.it_value.tv_usec = 250000;
/* ... and every 250 msec after that. */
timer.it_interval.tv_sec = 0;
timer.it_interval.tv_usec = 250000;
/* Start a virtual timer. It counts down whenever this process is
executing. */
setitimer (ITIMER_REAL, &timer, NULL);
/* Do busy work. */
while (print_flag) {
sleep(1);
}
printf("job done bye bye\n");
exit(0);
}
有了这个设置,一切都很好,我得到了这个输出
...
timer expired 17 times
timer expired 18 times
timer expired 19 times
timer expired 20 times
timer expired 21 times
job done bye bye
如果我尝试更改注释timer.it_interval.tv_usec 和timer.it_interval.tv_usec 的代码并将timer.it_value.tv_sec 和timer.it_value.tv_sec 设置为例如3,它就无法完成他的工作。
但是,如果我像这样维护tv_usec 的显式声明,它会起作用:
timer.it_value.tv_sec = 3;
timer.it_value.tv_usec = 0;
timer.it_interval.tv_sec = 3;
timer.it_interval.tv_usec = 0;
为什么我在两个字段的 tv_usec 的显式声明上绑定?
【问题讨论】:
-
这可能不是您的麻烦的原因,但请参阅How to avoid using
printf()in a signal handler 以获取有关您可以在信号处理程序中调用哪些函数的信息。请注意,printf()不是这些函数之一,正式的(strlen()也不是——虽然我可以解释printf(),但我发现strlen()更难解释)。 -
谢谢我完全忘记了!
标签: c linux unix signals setitimer