【发布时间】:2020-05-10 19:40:43
【问题描述】:
我正在尝试使用 Mockery 模拟 Http 客户端,但是当我尝试传入返回值时,我收到一条错误消息:type http.Response is not an expression
下面是我的界面和处理程序
type HTTPClient interface {
Get(url string) (resp *http.Response, err error)
}
type Handler struct {
httpClient HTTPClient
}
Mockery 生成了一个如下所示的模拟类
type HTTPClient struct {
mock.Mock
}
// Get provides a mock function with given fields: url
func (_m *HTTPClient) Get(url string) (*http.Response, error) {
ret := _m.Called(url)
var r0 *http.Response
if rf, ok := ret.Get(0).(func(string) *http.Response); ok {
r0 = rf(url)
} else {
if ret.Get(0) != nil {
r0 = ret.Get(0).(*http.Response)
}
}
var r1 error
if rf, ok := ret.Get(1).(func(string) error); ok {
r1 = rf(url)
} else {
r1 = ret.Error(1)
}
return r0, r1
}
在我的测试中,我试图像下面那样模拟 httpclient
httpClient := &mocks.HTTPClient{}
httpClient.On("Get", request.SubscribeURL).Return(resp*http.Response, nil)
我不确定我应该在 Return 中使用哪些参数。我应该通过什么?
【问题讨论】:
标签: unit-testing go mockery