在触发器中使用分隔符的 Mysql 错误答案

【问题标题】：Mysql Error for using Delimiters in triggers在触发器中使用分隔符的 Mysql 错误
【发布时间】：2015-10-30 18:40:47
【问题描述】：

这是我的mysql触发语句

DELIMITER |
CREATE TRIGGER kk AFTER UPDATE
    ON location FOR EACH ROW
 BEGIN
        IF NEW.name not in(SELECT A.name FROM filter A  WHERE (NEW.name = A.name))THEN  

        IF NEW.location_name != OLD.location_name THEN
            INSERT INTO filter(old_location_name,new_location_name) 
            VALUES (OLD.location_name, NEW.location_name);

        ELSE
            
                UPDATE filter SET old_location_name = OLD.location_name , new_location_name = NEW.location_name WHERE name = OLD.name;  

        END IF; 

        ELSE

            UPDATE filter SET old_location_name = OLD.location_name , new_location_name = NEW.location_name WHERE name = OLD.name;

  
        END IF; 
              
  END;|
DELIMITER ;

当我将此代码粘贴到 phpMyadmin 中时，这工作正常。

在我的项目中

$sqlDrop = "DROP TRIGGER IF EXISTS `kk`";       
$resDrop = parent::_executeQuery($sqlDrop); 

echo $sql = "same above delimiter trigger query";
$rs = parent::_executeQuery($sql );

现在$sql 语句在一行中回显

 DELIMITER | CREATE TRIGGER kk AFTER UPDATE ON location FOR EACH ROW BEGIN IF NEW.name not in(SELECT A.name FROM filter A  WHERE (NEW.name = A.name))THEN IF NEW.location_name != OLD.location_name THEN INSERT INTO filter(old_location_name,new_location_name,name) VALUES (OLD.location_name, NEW.location_name);    ELSE UPDATE filter SET old_location_name = OLD.location_name , new_location_name = NEW.location_name WHERE name = OLD.name; END IF; ELSE UPDATE filter SET old_location_name = OLD.location_name , new_location_name = NEW.location_name WHERE name = OLD.name; END IF; END;| DELIMITER ;

并且查询没有被执行。当我将回显语句粘贴到我的 phpMyadmin 中时，它向我显示了一个错误

那么可能是什么问题。这是执行触发器查询的正确方法吗？

【问题讨论】：

标签： php mysql triggers phpmyadmin delimiter

【解决方案1】：

不确定是否有任何与 PHP 相关的问题，但请尝试修改您的触发代码，如下所示

DELIMITER |
CREATE TRIGGER kk AFTER UPDATE
    ON location FOR EACH ROW
 BEGIN
        IF NEW.name not in(SELECT A.name FROM filter A  WHERE NEW.name = 
A.name) AND NEW.location_name != OLD.location_name THEN      
            INSERT INTO filter(old_location_name,new_location_name) 
            VALUES (OLD.location_name, NEW.location_name);    
        ELSE    
                UPDATE filter SET old_location_name = OLD.location_name ,
 new_location_name = NEW.location_name WHERE name = OLD.name;      
        END IF;     
END;|
DELIMITER ;

【讨论】：

【解决方案2】：

我不确定这是否真的对你有帮助。分别执行每个查询怎么样？

$startDelimit = 'DELIMITER |';
$resStart = parent::_executeQuery($startDelimit);

然后你的创建触发器语句

$sql = "CREATE TRIGGER kk AFTER UPDATE ...... END IF; END;";
$rs = parent::_executeQuery($sql );

然后是最后一条语句

$endDelimit = '| DELIMITER ;';
$resEnd = parent::_executeQuery($endDelimit );

【讨论】：