【发布时间】:2015-02-16 18:13:38
【问题描述】:
我正在尝试使用node js 和express 为我的数据库设置REST api。
现在我一直是分而治之的粉丝,因此我对创建REST api in node js 时将获得的冗余代码和大量服务器文件感到有些不安。
以对用户表的CRUD 操作为例:
// IMPORT ROUTES
// =============================================================================
var router = express.Router();
// on routes that end in /users
// ----------------------------------------------------
router.route('/user')
// create a user (accessed at POST http://localhost:8080/api/users)
.post(function (req, res) {
var username = req.body.username; //bodyParser does the magic
var password = req.body.password;
var user = User.build({username: username, password: password});
user.add(function (success) {
res.json({message: 'User created!'});
},
function (err) {
res.status(err).send(err);
});
})
// get all the users (accessed at GET http://localhost:8080/api/users)
.get(function (req, res) {
var user = User.build();
user.retrieveAll(function (users) {
if (users) {
res.json(users);
} else {
res.status(401).send("User not found");
}
}, function (error) {
res.status("User not found").send('user not found');
});
});
var User = sequelize.define('user', {
id: DataTypes.INTEGER,
username: DataTypes.STRING,
password: DataTypes.STRING,
name: DataTypes.STRING,
organization_id: DataTypes.INTEGER,
type_id: DataTypes.INTEGER,
join_date: DataTypes.STRING,
image_path: DataTypes.STRING,
status_id: DataTypes.INTEGER
}, { freezeTableName: true,
instanceMethods: {
retrieveAll: function (onSuccess, onError) {
User.findAll({}, {raw: true})
.ok(onSuccess).error(onError);
},
retrieveById: function (user_id, onSuccess, onError) {
User.find({where: {id: user_id}}, {raw: true})
.success(onSuccess).error(onError);
},
add: function (onSuccess, onError) {
var username = this.username;
var password = this.password;
var shasum = crypto.createHash('sha1');
shasum.update(password);
password = shasum.digest('hex');
User.build({username: username, password: password})
.save().ok(onSuccess).error(onError);
},
updateById: function (user_id, onSuccess, onError) {
var id = user_id;
var username = this.username;
var password = this.password;
var shasum = crypto.createHash('sha1');
shasum.update(password);
password = shasum.digest('hex');
User.update({username: username, password: password}, {where: {id: id}})
.success(onSuccess).error(onError);
},
removeById: function (user_id, onSuccess, onError) {
User.destroy({where: {id: user_id}}).success(onSuccess).error(onError);
}
}
}
);
// on routes that end in /users/:user_id
// ----------------------------------------------------
router.route('/users/:user_id')
// update a user (accessed at PUT http://localhost:8080/api/users/:user_id)
.put(function (req, res) {
var user = User.build();
user.username = req.body.username;
user.password = req.body.password;
user.updateById(req.params.user_id, function (success) {
console.log(success);
if (success) {
res.json({message: 'User updated!'});
} else {
res.send(401, "User not found");
}
}, function (error) {
res.send("User not found");
});
})
// get a user by id(accessed at GET http://localhost:8080/api/users/:user_id)
.get(function (req, res) {
var user = User.build();
user.retrieveById(req.params.user_id, function (users) {
if (users) {
res.json(users);
} else {
res.status(401).send("User not found");
}
}, function (error) {
res.send("User not found");
});
})
// delete a user by id (accessed at DELETE http://localhost:8080/api/users/:user_id)
.delete(function (req, res) {
var user = User.build();
user.removeById(req.params.user_id, function (users) {
if (users) {
res.json({message: 'User removed!'});
} else {
res.status(401).send("User not found");
}
}, function (error) {
res.send("User not found");
});
});
现在这只适用于一张桌子。
所以我认为必须有更好的方法来组织所有这些?
所以我的问题是你能把每条路由分成一个单独的文件吗?有没有办法简化数据的路由/收集,从而消除冗余?
【问题讨论】:
-
您可以将代码放入多个文件中,然后将它们包含在主
server.js -
@VsevolodGoloviznin 你能发布一个例子来说明你如何做到这一点吗?
标签: javascript node.js rest url-routing