【发布时间】:2018-02-03 19:11:46
【问题描述】:
OC 1.5.6
我安装了一个模块来根据制造商筛选产品类别。
我可以通过如下网址访问每个“搜索结果页面”:
example.com/index.php?route=product/category&path=X&manufacturer=Y
我想创建一个 SEO 网址,例如:
example.com/alias-for-category/alias-for-manufacturer
(例如 /bikes/honda 或 /cars/bmw)
但我不知道该怎么做。
我尝试过测试和简化以仅转换单个网址:
product/category&path=1&manufacturer=1
所以我向url_alias 添加了一条包含此查询和关键字的记录
cat1-man1
然后我修改了catalog/common/seo_url.php
功能索引
if (isset($this->request->get['product_id'])) {
$this->request->get['route'] = 'product/product';
} elseif (isset($this->request->get['path'])) {
$this->request->get['route'] = 'product/category';
} elseif (isset($this->request->get['manufacturer_id'])) {
$this->request->get['route'] = 'product/manufacturer/info';
} elseif (isset($this->request->get['information_id'])) {
$this->request->get['route'] = 'information/information';
}
//ADDED BELOW CODE TO ROUTE ALL URL
else {
$query = $this->db->query("SELECT * FROM " . DB_PREFIX . "url_alias WHERE keyword = '" . $this->db->escape($this->request->get['_route_']) . "'");
if ($query->num_rows) {
$this->request->get['route'] = $query->row['query'];
}
}
和函数重写
if (($data['route'] == 'product/product' && $key == 'product_id') || (($data['route'] == 'product/manufacturer/info' || $data['route'] == 'product/product') && $key == 'manufacturer_id') || ($data['route'] == 'information/information' && $key == 'information_id')) {
$query = $this->db->query("SELECT * FROM " . DB_PREFIX . "url_alias WHERE `query` = '" . $this->db->escape($key . '=' . (int)$value) . "'");
if ($query->num_rows) {
$url .= '/' . $query->row['keyword'];
unset($data[$key]);
}
} elseif ($key == 'path') {
$categories = explode('_', $value);
foreach ($categories as $category) {
$query = $this->db->query("SELECT * FROM " . DB_PREFIX . "url_alias WHERE `query` = 'category_id=" . (int)$category . "'");
if ($query->num_rows) {
$url .= '/' . $query->row['keyword'];
}
}
unset($data[$key]);
}
//ADDED CODE BELOW TO CONVERT ALL URL
else {
$query = $this->db->query("SELECT * FROM " . DB_PREFIX . "url_alias WHERE `query` = '" . $this->db->escape($data['route']) . "'");
if ($query->num_rows) {
$url .= '/' . $query->row['keyword'];
unset($data[$key]);
}
}
而且这个简化版根本不起作用,显示找不到页面。
我做错了什么?任何提示将不胜感激
【问题讨论】:
-
你检查过它是否在你的
else条件下,也许它在这个条件下elseif (isset($this->request->get['path'])) { $this->request->get['route'] = 'product/category'; }