【问题标题】:React component Game not rendered with route反应组件游戏未使用路由渲染
【发布时间】:2018-06-08 11:47:46
【问题描述】:

我正在尝试使用路由渲染游戏组件。单击链接(在 app.js 中定义)时,它会指向所需的页面(游戏),但不会呈现组件 Game。我试图找到答案,但没有一个有帮助。我对反应完全陌生。请帮忙!!谢谢你!! 以下是sn-ps的代码:

index.js

import React from 'react';
import ReactDOM from 'react-dom';
import './index.css';
import App from './App.js';
import Game from './Game.js';
import registerServiceWorker from './registerServiceWorker';
import {
  HashRouter,
  Route,
  Link,
  BrowserRouter as Router
} from 'react-router-dom';

ReactDOM.render(
  <Router>
      <Route exact path = "/" component={App}>
          <Route path="game" component={Game}></Route>
      </Route>
   </Router >,
  document.getElementById('root')
);

App.js

import React, { Component } from 'react';
import './App.css';
import { Link } from 'react-router-dom'


class App extends Component {

  render() {
    return (
      <div>
      <Link to= "game">Go</Link>
      {this.props.children}
      </div>
    );
  }
}

export default App;

Game.js

import React from 'react';
import './index.css';
import registerServiceWorker from './registerServiceWorker';



function Square(props) {
  return (
    <button className="square" onClick={props.onClick}>
      {props.value}
    </button>
  );
}

export class Board extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
      squares: Array(9).fill(null),
      xIsNext: true,
    };
  }

  handleClick(i) {
    const squares = this.state.squares.slice();
    if (calculateWinner(squares) || squares[i]) {
      return;
    }
    squares[i] = this.state.xIsNext ? 'X' : 'O';
    this.setState({
      squares: squares,
      xIsNext: !this.state.xIsNext,
    });
  }

  renderSquare(i) {
    return (
      <Square
        value={this.state.squares[i]}
        onClick={() => this.handleClick(i)}
      />
    );
  }

  render() {
    const winner = calculateWinner(this.state.squares);
    let status;
    if (winner && winner != 'draw') {
      status = 'Winner: ' + winner;
    }
    else if (winner && winner === 'draw'){
            status = "Both won!! It's a tie!! ";
    }
    else {
      status = 'Next player: ' + (this.state.xIsNext ? 'X' : 'O');
    }

    return (
      <div>
        <div className="status">{status}</div>
        <div className="board-row">
          {this.renderSquare(0)}
          {this.renderSquare(1)}
          {this.renderSquare(2)}
        </div>
        <div className="board-row">
          {this.renderSquare(3)}
          {this.renderSquare(4)}
          {this.renderSquare(5)}
        </div>
        <div className="board-row">
          {this.renderSquare(6)}
          {this.renderSquare(7)}
          {this.renderSquare(8)}
        </div>

      </div>
    );
  }
}

export default class Game extends React.Component {
  render() {
    return (
      <div className="game">
        <div className="game-board">
          <Board />
        </div>
      </div>
    );
  }
}

function calculateWinner(squares) {
  const lines = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ];
  for (let i = 0; i < lines.length; i++) {
    const [a, b, c] = lines[i];
    if (squares[a] && squares[a] === squares[b] && squares[a] === squares[c]) {
      return squares[a];
    }
    else if(!squares.includes(null)) {
            return 'draw';
    }
  }
  return null;
}

registerServiceWorker();

【问题讨论】:

    标签: javascript reactjs


    【解决方案1】:

    你为什么要包裹一条路线?

    试试这个:

    <Route exact path="/" component={App} />
    <Route path="/game" component={Game} />
    

    路由应该被视为兄弟,它们也按照编写的顺序工作。

    查看此页面了解更多信息:https://reacttraining.com/react-router/web/example/basic

    编辑路由器示例: 用这个替换你的路由器。

    <Router>
        <div>
            <Route exact path="/" component={App} />
            <Route path="/game" component={Game} />
        </div>
    </Router>
    

    【讨论】:

    • 我试图将两条路线分别放在一个 div 中。它仍然没有渲染游戏.. :(
    • 路由器>
    • 没有 div 会显示错误。 可能只有一个子元素
    • 能否请您解释一下之前的问题?我正在学习..
    • 您的语法有一些小问题,您的游戏路径在“游戏”之前没有必需的“/”。您也不需要关闭路由标签,只需用 / 结束它,就像这样 &lt;Route ... /&gt;
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