如何将另一个函数的返回值调用到一个新函数中？

Question

我只是遇到了一些功能问题。我写了一个函数：

def dep():
  d = int(input("when did the employee depart? Please enter response in military time 0 - 2400 "))
  while (d < 0 or d > 2400):
      d= int(input("Please enter a valid number "))
return d

在后面的函数中，我想要值 d。如此处所示：

def mealDep(): 
  dep = dep() 

  if dep <= 700 and dep > 0:

我现在知道我不能只调用 dep() 并将其分配给变量，但是如何获取返回的值呢？

Answer 1

我去清理了几个错误，并让其他事情变得更好。除了使用 dep = ... 隐藏您自己的函数之外，还有其他一些事情，例如不安全地投射用户输入。希望这会有所帮助。

def get_departure_time():  # verbosity is GOOD 99% of the time

    while True:
        # Get the raw input first
        departure_time = input("When did the employee depart? Please enter response in military time 0 - 2400:")

        # THEN validate. This prevents your code from breaking from type conversion
        try:
            departure_time = int(departure_time)
            assert departure_time > 0 and departure_time < 2400

            break # Breaks out of the infinite loop, and returns below

        except (ValueError, AssertionError):
            print("Please enter response in military time 0 - 2400.")
            continue

    return departure_time

def meal_dep(): #  snek_case > camelback case
    departure_time = get_departure_time() 

    if departure_time <= 700 and departure_time > 0:
        ...