【发布时间】:2013-04-05 14:20:54
【问题描述】:
由于不够清晰,我重新编辑了我的问题。下面的代码获取一个随机数,然后检查它是否是一个新高,如果是一个则记录它。然后经过一定的延迟(1 分钟)后,它会再次执行相同的操作,从上一周期的最后一个数字开始。
我想在不同的频率上运行相同的,所以我会有很多时间段,我是否应该在函数中重写下面的代码,例如,我可以获得 agregateinfrequency(5min),它只会返回下面的打印(或列表)
希望现在更有意义。
for random_number, current_time,i in generator():
previous_last_price = mynumber
mynumber = mynumber + (random_number*0.0001)
#print (random_number*0.01)
if mynumber >high_price: #new one
high_price = mynumber
if mynumber <low_price: #new one
low_price = mynumber
last_price = mynumber
if keyfunc(current_time,1) != previous_reftime1min: #new one
print mynumber,",",i, current_time,",", keyfunc(current_time,1),",", previous_reftime1min,",", open_price,",", high_price,",", low_price,",", last_price
wrtr.writerow([mynumber, i,current_time, keyfunc(current_time,1), previous_reftime1min, open_price, high_price, low_price, last_price])
myfile.flush() # whenever you want, and/or
open_price = previous_last_price
high_price = mynumber
low_price = mynumber
last_price = mynumber
previous_reftime1min = keyfunc(current_time,1)
【问题讨论】:
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你有什么问题?
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我编辑了问题
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缩进是怎么回事...?
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如果您需要在输入范围内多次重复此计算,则可以使用
for循环。您可以清理代码并将其放入 for 循环中的函数调用中,但对于不一定那么重要的小脚本。 -
我知道这看起来很愚蠢,但我从来不明白如何在网站上保留 indetation,我点击“代码”它说在这里输入代码,然后我粘贴我的代码,我应该做其他事情吗?