【发布时间】:2021-02-04 22:48:07
【问题描述】:
这是我的代码
import smtplib
from datetime import datetime
print("Sending Mail")
with smtplib.SMTP('smpt.gmail.com', 587) as smtp:
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('gmail', 'password')
print("Logged In")
subject = "Current Time: " + datetime.now.strftime("%d/%m/%Y %H:%M:%S")
smtp.sendmail('myemail@gmail.com', 'myemail@gmail.com', "hello")
print("Sent Email")
我正在尝试使用 smtplib 通过 gmail 发送电子邮件,这是我得到的错误:
Sending Mail
Traceback (most recent call last):
File "c:/Users/12488/Downloads/Key Logger/keylog.py", line 43, in <module>
with smtplib.SMTP('smpt.gmail.com', 587) as smtp:
File "C:\Users\12488\AppData\Local\Programs\Python\Python38\lib\smtplib.py", line 253, in __init__
(code, msg) = self.connect(host, port)
File "C:\Users\12488\AppData\Local\Programs\Python\Python38\lib\smtplib.py", line 339, in connect
self.sock = self._get_socket(host, port, self.timeout)
File "C:\Users\12488\AppData\Local\Programs\Python\Python38\lib\smtplib.py", line 308, in _get_socket
return socket.create_connection((host, port), timeout,
File "C:\Users\12488\AppData\Local\Programs\Python\Python38\lib\socket.py", line 787, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:\Users\12488\AppData\Local\Programs\Python\Python38\lib\socket.py", line 918, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11001] getaddrinfo failed
我确保在 gmail 上检查了不太安全的设备,但我没有尝试过互联网上的所有解决方案,因为我是 python 新手,这是我第一次使用 smtp,但我没有得到很多,我认为这与套接字有关,因为这是我读过的另一个流行的 python 模块,但我不太了解它,我不确定是否有人可以简化问题并向我解释我是 5 岁,将不胜感激。
【问题讨论】:
-
smpt.gmail.com应该是smtp.gmail.com
标签: python python-3.x smtp gmail smtplib