Python 2：如何将元组中的参数传递给函数？ [复制]

Question

我想将参数元组 args （元组的长度因其他一些函数而变化）传递给一个函数，该函数有效

def myf(x1,x2,x3,....)
    return something involving x1,x2....

args = (y1,y2,.....)

call myf with args as myf(y1,y2,....)

您是如何做到这一点的？在我的实际问题中，我正在使用sympy 函数myf 实际上是reshape 而变量参数列表args 是通过获取一些n-d 数组的形状生成的元组，比如A，所以args = A.shape。最后我想根据A的形状重塑另一个数组B。一个最简单的例子

from sympy import *
A = Array(symbols('a:2:3:4:2'),(2,3,4,2))
B = Array(symbols('b:8:3:2'),(8,3,2))
args = A.shape
print args
print B.reshape(2,3,4,2) # reshape(2,3,4,2) is the correct way to call it
print B.reshape(args) # This is naturally wrong since reshape((2,3,4,2)) is not the correct way to call reshape

Answer 1

使用参数解包：

def myf(x1,x2,x3):
    return x1 + x2 + x3

args = (1, 2, 3)

myf(*args)  # 6

Answer 2

你需要解压元组：

B.reshape(*args)