【发布时间】:2012-03-19 09:25:39
【问题描述】:
如何使用变量中的字符串在 CSV 文件的末尾添加一列?
输入.csv
2012-02-29,01:00:00,Manhattan,New York,234
2012-02-29,01:00:00,Manhattan,New York,843
2012-02-29,01:00:00,Manhattan,New York,472
2012-02-29,01:00:00,Manhattan,New York,516
输出.csv
2012-02-29,01:00:00,Manhattan,New York,234,2012-02-29 16:13:00
2012-02-29,01:00:00,Manhattan,New York,843,2012-02-29 16:13:00
2012-02-29,01:00:00,Manhattan,New York,472,2012-02-29 16:13:00
2012-02-29,01:00:00,Manhattan,New York,516,2012-02-29 16:13:00
awk.sh
#!/bin/bash
awk -F"," '{$6="2012-02-29 16:13:00" OFS $6; print}' input.csv > output.csv
我在 awk.sh 中的尝试将字符串添加到末尾,但去掉了所有逗号分隔符。
awk.sh 结果
2012-02-29 01:00:00 Manhattan New York 234 2012-02-29 16:13:00
2012-02-29 01:00:00 Manhattan New York 843 2012-02-29 16:13:00
2012-02-29 01:00:00 Manhattan New York 472 2012-02-29 16:13:00
2012-02-29 01:00:00 Manhattan New York 516 2012-02-29 16:13:00
感谢任何帮助!
更新了 awk.sh
#!/bin/bash
GAWK="/bin/gawk"
TIMESTAMP=$(date +"%F %T")
ORIG_FILE="input.csv"
NEW_FILE="output.csv"
#Append 'Create' DateTimeStamp to CSV for MySQL logging
$GAWK -v d="$TIMESTAMP" -F"," 'BEGIN {OFS = ","} {$6=d; print}' $ORIG_FILE > $NEW_FILE
rm -f $ORIG_FILE
【问题讨论】:
-
不是“ManhattAn”而不是“ManhattEn”吗?
-
可能是,我只是快速键入它作为示例。