用于查找两个文件之间出现次数增加的 Shell 脚本

Question

文件1.log

2000 apple
2333 cat
5343 dog
1500 lion

文件2.log

2500 apple
2333 cat
1700 lion

需要一个shell脚本来输出如下：

500 apple
200 lion

尝试了很多解决方案，但没有任何解决方案，因为我同时拥有文本和字符串。有人可以帮忙吗。谢谢

编辑（由 RavinderSingh13 提供）：将 OP 在 cmets 中显示的 OP 的努力添加到帖子中：

#!/bin/bash
input1="./File1.log"
input2="./File2.log"
while IFS= read -r line2
do
  while IFS=read -r line1
  do
     echo "$line1"
  done < "$input1"
  echo "$line2"
done < "$input2"

Answer 1

请您尝试关注一下。

awk 'FNR==NR{a[$2]=$1;next} $2 in a && ($1-a[$2])>0{print $1-a[$2],$2}' file1 file2

添加上述解决方案的非单行形式：

awk '
FNR==NR{
  a[$2]=$1
  next
}
($2 in a) && ($1-a[$2])>0{
  print $1-a[$2],$2
}
'  Input_file1  Input_file2

说明：在此处添加对上述解决方案的详细说明。

awk '                             ##Starting awk program from here.
FNR==NR{                          ##Checking condition if FNR==NR which will be TRUE once file1 is being read then do following.
  a[$2]=$1                        ##Creating an array a whose index is $2 and value is $1 of current line.
  next                            ##Using next function of awk, to skip all further lines from here.
}                                 ##Closing condition BLOCK for FNR==NR here.
($2 in a) && ($1-a[$2])>0{        ##Checking condition if $2 is present in array a AND difference of $1 and array a with index $2 is greater than 0 then do following.
  print $1-a[$2],$2               ##Printing difference between $1 and array a with index $2 along with current $2 here.
}                                 ##Closing BLOCK for above condition here.
' file1 file2                     ##Mentioning Input_file names here.

Answer 2

awk '{if (!($2 in entry)) { entry[$2]=$1 } else { delta=$1-entry[$2]; if (delta!=0) {print delta,$2} } }' FILE_1 FILE2

您也可以将其放入文件中，例如delta.awk:

{
  if (!($2 in entry)) {
    entry[$2]=$1 
  } else { 
    delta=$1-entry[$2]
    if (delta !=0) { # Only output lines of non-zero increment/decrement
      print delta,$2
    } 
  } 
}

通过awk -f delta.awk FILE_1.txt FILE_2.txt调用。