使用 JOIN 从不同的表中检索多个数据值答案

【问题标题】：retrieve multiple data value from different tables using JOIN使用 JOIN 从不同的表中检索多个数据值
【发布时间】：2019-07-27 05:17:00
【问题描述】：

我有三张桌子。 1. bni_category 2. bni_章节 3. bni_member

CREATE TABLE `bni_category` (
 `bni_category_id` int(11) NOT NULL,
 `bni_category_name` text,
 `is_active` int(1) NOT NULL DEFAULT '1',
 `is_delete` int(1) NOT NULL DEFAULT '0',
 `last_update` datetime DEFAULT NULL,
 `bni_chapter_id` int(20) NOT NULL,
 create_date` varchar(50) NOT NULL,
    PRIMARY KEY (`bni_category_id`),
 KEY `bni_chapter_id` (`bni_chapter_id`),
 CONSTRAINT `bni_category_ibfk_1` FOREIGN KEY (`bni_chapter_id`) 
REFERENCES `bni_chapter` (`bni_chapter_id`),
) ENGINE=InnoDB DEFAULT CHARSET=latin1

BNI_章节

CREATE TABLE `bni_chapter` (
 `bni_chapter_id` int(11) NOT NULL,
 `bni_chapter_name` varchar(50) DEFAULT NULL,
 `create_date` varchar(50) NOT NULL,
  `is_active` int(1) NOT NULL DEFAULT '1',
`is_delete` int(1) NOT NULL DEFAULT '0',
 `last_update` varchar(50) DEFAULT NULL,
 PRIMARY KEY (`bni_chapter_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1

BNI_member

 CREATE TABLE `bni_member` (
`bni_member_id` int(11) NOT NULL AUTO_INCREMENT,
 `bni_member_name` text,
 `bni_member_mobile` varchar(13) DEFAULT NULL,
 `bni_member_email` text,
 `bni_member_website` text,
 `bni_member_bio` text,
 `bni_member_export_to` text,
 `bni_member_import_from` text,
 `bni_member_want_to_connect_to` text,
 `bni_member_company` text,
 `bni_chapter_id` int(11) DEFAULT NULL,
 `bni_category_id` int(11) DEFAULT NULL,
 `bni_member_address` text,
 `bni_member_commitee` text,
 `bni_member_profilepic` longblob NOT NULL,
 `bni_member_logo` longblob NOT NULL,
 `create_date` timestamp NULL DEFAULT CURRENT_TIMESTAMP,
 `is_active` int(1) NOT NULL DEFAULT '1',
 `is_delete` int(1) NOT NULL DEFAULT '0',
 `last_update` text,
 `del_status` varchar(50) NOT NULL,
 PRIMARY KEY (`bni_member_id`),
 KEY `bni_chapter_id` (`bni_chapter_id`),
 KEY `bni_category_id` (`bni_category_id`),
  KEY `bni_member_id` (`bni_member_id`),
 CONSTRAINT `bni_member_ibfk_1` FOREIGN KEY (`bni_chapter_id`) REFERENCES 
`bni_chapter` (`bni_chapter_id`),
 CONSTRAINT `bni_member_ibfk_2` FOREIGN KEY (`bni_category_id`) 
REFERENCES `bni_category` (`bni_category_id`)
) ENGINE=InnoDB AUTO_INCREMENT=223 DEFAULT CHARSET=latin1

现在我想显示 bni_member_name bni_member_id bni_chapter_id bni_chapter_name bni_category_id bni_category_name FROM bni_member 和章节id，章节名称形成章节表和类别id，类别名称形成类别表。

决赛桌应该看起来像

Member Id | Member Name | Chapter Id | Chapter Name | Category Id 
|category Name

【问题讨论】：

您是否尝试过任何使用联接的查询？
是的，我使用了交叉连接。 @user1309690
您能否显示您的查询以及使用该查询得到的输出。
"SELECT * FROM bni_member CROSS JOIN bni_chapter CROSS JOIN bni_category WHERE bni_member_id = '".$_POST["employee_id"]."'"; 但它一次又一次地提供相同的数据。 @user1309690
但我认为它不起作用。它给出了错误的数据。你能帮忙吗..@user1309690

标签： php mysql sql-query-store

【解决方案1】：

请尝试以下查询。

SELECT A.bni_member_id, A.bni_member_name, A.bni_chapter_id, B.bni_chapter_name,  A.bni_category_id, C.bni_category_name FROM `bni_member` AS a LEFT JOIN `bni_chapter` as B on A.bni_chapter_id = B.bni_chapter_id left join `bni_category` AS C on A.bni_category_id = C.bni_category_id

【讨论】：