每个字符串每出现第 2 次，分别用文件的第 n 行替换两个不同的字符串

Question

我正在尝试使用以下command_line01 将home_cool 的第一次和第二次出现分别替换为1.txt 的第一行，然后继续替换home_cool01 的第一次和第二次出现也分别由1.txt 的第一行，然后..，用1.txt 的第二行单独替换第三和第四次出现的home_cool。等等，即每2 nth 出现home_cool 或home_cool01，分别用1.txt 的第n 行替换两个字符串。

我试过command_line01 波纹管：

awk 'NR==FNR {a[NR]=$0; next} /home_cool01/{gsub("home_cool01", a[++i<3])} /home_cool/{gsub("home_cool", a[++j<3])} 1' 1.txt 0.txt > 2.txt

但这仅适用于 前两次出现，因为接下来的两次出现 home_cool 或 home_cool01 被 nothing 替换，如下所示：

"#sun\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree()\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree()\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree()\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree()\t",
"machine(shoes_shirt.shop)\t",

这是我的两个源文件：

0.txt：

"#sun\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tre(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",

和

1.txt：

(food, apple, sky, cat,blue,)(bag, tortoise,)
(food, apple, sky, cat,blue,)(bag,)
(food, apple, sky, cat,blue,)(bag, moon, tortoise,)

而我想要的输出 2.txt 是：

"#sun\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",

编辑：来自@markp-fuso cmets：

1 - 如果有多个条目，如果已​​经完成第一个条目的处理，我将从第二个重新启动。

2 - 如果我有超过 6 个 home_coool 条目...我从 1.txt 的开头继续。

3 - 我不想仅限于两种研究模式，所以当有home_coool02、home_coool03、...、home_coool_some_sufix 时，它应该是一个合适的解决方案，但我需要保持我最初发布的 MWE

Answer 1

假设：

• 只需要担心搜索模式 home_cool 和 home_cool01（可以添加更多，但需要一些返工；可能使用关联数组来跟踪每个唯一模式的计数）
• 在继续下一个替换模式之前，将应用两次替换模式
• 如果我们到达替换模式的末尾，我们会从头开始

示例输入：

$ cat 0.txt
"#sun\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool01)\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",          # pick up where we left off with 'home_cool'
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",          # restart from beginning of 0.txt replacment patterns
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree(home_cool)\t",
"machine(shoes_shirt.shop)\t",

一个awk想法：

awk '
NR==FNR       { a[NR]=$0; n=NR; next}
/home_cool01/ { gsub("home_cool01", a[int((i++)%(n*2)/2)+1])}
/home_cool/   { gsub("home_cool",   a[int((j++)%(n*2)/2)+1])}
1
' 1.txt 0.txt

地点：

• n==3 - 1.txt 中的行数；所以n*2 == 6
• %6 - 将生成 0-5 的输出
• (%6/2) - 将输出转换为 0.0, 0.5, 1.0, 1.5, 2.0, 2.5
• int(...) - 将输出变成0, 0, 1, 1, 2, 2
• +1 - 为我们提供1, 1, 2, 2, 3, 3 的数组索引
• 注意： 是的，索引有点复杂；我愿意接受简化的建议

这会生成：

"#sun\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, moon, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, moon, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",
"car_snif = house.group_tree((food, apple, sky, cat,blue,)(bag, tortoise,))\t",
"machine(shoes_shirt.shop)\t",