PHP：循环不断从 SQL 中检索所有用户，而不是一次只检索一个用户

Question

这里的概念是数据库将 youtube 频道用户名存储在一个名为 YOUTUBE 的单元格中。

我需要代码来查找 USERDB、查找 YOUTUBE 单元格并检索存储在列表中的所有用户名（任何空白单元格都不会显示）。

从这里开始，我需要将用户 YouTube 用户名从 YOUTUBE 单元格放入 FEEDURL 的代码

我需要这个循环，以便它可以从结果中执行每个单独的用户。我遇到的问题是 FEEDURL 在 URL 中显示所有用户的用户名而不是一个。

EG。 http://gdata.youtube.com/feeds/api/users/PewDiePie,MissFushi/uploads?max-results=13

但我需要它像

EG。 http://gdata.youtube.com/feeds/api/users/MissFushi/uploads?max-results=13

这是我的代码

$communityvideos = mysql_query("SELECT youtube FROM userdb WHERE rights='user' && youtube IS NOT NULL");
while($youtube = mysql_fetch_array($communityvideos)) {

$v[] = $youtube["youtube"];
}

$youtube2 = implode(',', array_filter($v));

$usernames = array($youtube2);

error_reporting(E_ALL);
foreach ($usernames as $user) {
$feedURL = 'http://gdata.youtube.com/feeds/api/users/' . $user .'/uploads?max-results=13';
$sxml = simplexml_load_file($feedURL);
}
$i=0;
foreach ($sxml->entry as $entry) {
      $media = $entry->children('media', true);
      $watch = (string)$media->group->player->attributes()->url;
      $thumbnail = (string)$media->group->thumbnail[0]->attributes()->url;

parse_str( parse_url( $watch, PHP_URL_QUERY ), $my_array_of_vars);

最后我只想要总共显示 13 个视频。不是来自每个用户的 13 个视频，而是来自所有加入的用户的 13 个视频。有什么想法吗？

Answer 1

尝试使用此代码。我对数组的操作方式进行了一些编辑。确保开始使用mysqli_* 扩展而不是mysql_*，因为前者更安全且不易出现SQL injection。

$communityvideos = mysql_query("SELECT youtube FROM userdb WHERE rights='user' && youtube IS NOT NULL");
$usernames = array();
while($youtube = mysql_fetch_assoc($communityvideos)) {
    $usernames[] = $youtube['youtube'];
}

//Redacted this does not do what you want it to do. This glues all usernames together and wrecks the $usernames array.
//$youtube2 = implode(',', array_filter($v));
//$usernames = array($youtube2);

error_reporting(E_ALL);

foreach ($usernames as $user){
$feedURL = 'http://gdata.youtube.com/feeds/api/users/' . $user .'/uploads?max-results=13';
$sxml = simplexml_load_file($feedURL);


// Place this inside the $usernames loop
$i=0;
foreach ($sxml->entry as $entry) {
      $media = $entry->children('media', true);
      $watch = (string)$media->group->player->attributes()->url;
      $thumbnail = (string)$media->group->thumbnail[0]->attributes()->url;

        parse_str( parse_url( $watch, PHP_URL_QUERY ), $my_array_of_vars);
        // And whatever came after this it doesn't show in the question.
    }
}

// You will have to figure the part below as well. Since you the last iteration of your foreach loop above will end with the last result in $sxml.
// The loop below will only loop the xml for the last result 

Answer 2

您不需要使用implode 来获取用户名。 只需直接使用for each 和array_filter($v) 结果：

$users = array_filter($v);
foreach ($users as $user) {
$feedURL = 'http://gdata.youtube.com/feeds/api/users/' . $user .'/uploads?max-results=13';
$sxml = simplexml_load_file($feedURL);
}

Answer 3

ommunityvideos = mysql_query("SELECT * FROM userdb WHERE rights='user' && youtube IS NOT NULL");
while($youtube = mysql_fetch_assoc($communityvideos)) {
    $v[] = $youtube['youtube'];

error_reporting(E_ALL);
$usernames = array_filter($v);
foreach ($usernames as $user){
$feedURL = 'http://gdata.youtube.com/feeds/api/users/' . $user .'/uploads?max-results=13';
$sxml = simplexml_load_file($feedURL);
$i=0;

foreach ($sxml->entry as $entry) {
      $media = $entry->children('media', true);
      $watch = (string)$media->group->player->attributes()->url;
      $thumbnail = (string)$media->group->thumbnail[0]->attributes()->url;

        parse_str( parse_url( $watch, PHP_URL_QUERY ), $my_array_of_vars);

对于任何阅读并想知道它最终如何修复的人？嗯，就在这里