在 API 响应中循环遍历字典答案

【问题标题】：Looping through dictionary in API response在 API 响应中循环遍历字典
【发布时间】：2021-06-24 09:09:08
【问题描述】：

我有一本大字典作为 API 响应，

{totalHits: 379730, currentPage: 1, totalPages: 7595, pageList: 

Array(10), foodSearchCriteria: {…}, …}
aggregations: {dataType: {…}, nutrients: {…}}
currentPage: 1
foodSearchCriteria: {pageNumber: 1, numberOfResultsPerPage: 50, pageSize: 50, requireAllWords: false}
foods: (50) [{…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}]
pageList: (10) [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
totalHits: 379730
totalPages: 7595
__proto__: Object

我怎样才能循环获取每个页面的食物数组中的每种食物（总数：7595）？

也可以通过 python-requests 来完成。

【问题讨论】：

标签： javascript response

【解决方案1】：

async function fetchFoodData() {
  let foods = [];
  let morePagesAvailable = true;
  let currentPage = 0;

  while(morePagesAvailable) {
    currentPage++;
    const response = await fetch(`http://yourapiurl.io/restlt?page=${currentPage}`)
    let food = await response.json();
    foods.push(food);
    morePagesAvailable = currentPage < total_pages;
  }

  return foods;
}

【讨论】：