如何创建正确的 while 循环？

Question

我正在尝试创建一个简单的猜数字游戏。据我了解，如果用户输入不等于 RNG 生成的数字，我可以使用 while 循环作为正确的 goto 函数。包括我创建的代码。我要做的是告诉程序如果x<y，print("Too low. Try again")，然后循环返回以询问用户输入。 x>y 的原理相同。当数字猜对时，它应该显示一条消息，要求输入 Y/N，然后关闭程序或循环回到开头。我该怎么做呢？

我尝试过包含一个 while 循环，但我遇到了以下问题：假设 RNG 生成 50。如果我猜为 49，它会打印 x<y 消息，要求另一个输入，但它会即使在新输入 x>y 或 x==y 中，也会继续显示 x<y 消息。

另外，当答案被正确猜到时，我不知道该怎么做，所以如果他们回答 Y，程序会重新启动。

最后，当游戏提示用户回答 Y/N 时，终端会在用户输入之前不知道为什么会显示字母“Y”。

print()
print("Guess an integer between 1-100.")
import random
y=random.randint(1,101)
print(y)
x=int(input())
if x==y:
    print(x, "is correct! Would you like to try again? Y/N")
    if input("Y"):
        print("Too bad! This game isn't finished yet!")
        exit()
    if input("N"):
        print("Good! This game isn't finished yet!")
        exit()
else:
    if x<y:
        print("Too low. Try again.")
    if x>y:
        print("Too high. Try again.")

Answer 1

好的，所以我不确定您的 if 语句和 while 循环系统是如何工作的，但我知道您错误地使用了输入函数。

如果你想检查输入是否等于a thing，你应该这样做：if input('>>> ') == 'a thing'

这将输出>>>，用户可以输入他们的响应，如果等于a thing，则返回true。

我想我知道这是做什么的，但我不确定。我将在本文的结尾写上我会做的事情。

if x==y:
    print(x, "is correct! Would you like to try again? Y/N")
    if input("Y"):
        print("Too bad! This game isn't finished yet!")
        exit()
    if input("N"):
        print("Good! This game isn't finished yet!")
        exit()
while True:
    if x<y:
        print("Too low. Try again.")
        int(input())
    if x>y:
        print("Too high. Try again.")
        int(input())

我认为您正在尝试检查用户是否可以一口气猜出它，然后告诉他们他们的猜测是过高还是过低。 我会这样做：

import random

print('guess a number game (1-100 range)')

y = random.randint(1, 101)

x = int(input('>>> '))

if x == y:
    print('yay, you got it first try')
    exit()
else:
    print('nope')
    while x != y:
        x = int(input('>>> '))
        if x < y:
            print('Too low!')
        elif x > y:
            print('Too high!')
        elif x == y:
            print('E P I C')
            exit()

这是一个示例输出：

guess a number game (1-100 range)
>>> 48
nope
>>> 50
Too high!
>>> 25
Too low!
>>> 35
Too low!
>>> 45
Too high!
>>> 40
Too low!
>>> 44
E P I C

我有一段时间没来这里了（哈哈），所以这可能不是最好的答案。不过，希望这会有所帮助！

Answer 2

我认为这就是您要寻找的模式。

import random

EXIT = False

while True:
  if EXIT:
     break
  y=random.randint(1,101)
  print("Random ",y)
  while not EXIT:
    print("Guess an integer between 1-100.")
    x=int(input())
    if x==y:
        print(x, "is correct! Would you like to try again? (Y/N)\n")
        z = input()
        if z == 'Y':
            print("Too bad! This game isn't finished yet!\n")
            break
        if z == 'N':
            print("Good! This game isn't finished yet!\n")
            EXIT = True
            break
    else:
        if x<y:
            print("Too low. Try again.\n")
        if x>y:
            print("Too high. Try again.\n")

输出将是。

Random  89
Guess an integer between 1-100.
20
Too low. Try again.

Guess an integer between 1-100.
100
Too high. Try again.

Guess an integer between 1-100.
89
89 is correct! Would you like to try again? (Y/N)

Y
Too bad! This game isn't finished yet!

Random  36
Guess an integer between 1-100.
36
36 is correct! Would you like to try again? (Y/N)

N
Good! This game isn't finished yet!