REST API，不能在我的 URL 中输入“%20”或“+”作为空格。未获取 URL

Question

我从控制台收到错误消息 org.springframework.web.client.HttpClientErrorException: 400 null，这意味着我的 URL 发送了服务器无法理解的错误请求。

但是，每当我输入一个没有 %20 或 + 符号的 URL 时

示例： http://ksr-ca-qmaltjira.ca.kronos.com:8061/rest/api/2/search?jql=project=SUP&maxResults=2 有效，我的数据显示在我的本地页面上。

String username = "confidential";
String password = "confidential";

private static final String jiraBaseURL = "http://ksr-ca-qmaltjira.ca.kronos.com:8061/rest/api/search?jql=project%3D%22Customer%20Support%22%20%26%20type%20%3D%20%22Change%20Request%22%20&maxResults=2";
private RestTemplate restTemplate;
private HttpHeaders httpHeaders;





private HttpHeaders createHeadersWithAuthentication() {
    String plainCreds = username + ":" + password;
    byte[] base64CredsBytes = Base64.getEncoder().encode(plainCreds.getBytes());
    String base64Creds = new String(base64CredsBytes);

    HttpHeaders headers = new HttpHeaders();
    headers.add("Authorization", "Basic " + base64Creds);

    return headers;
}




@RequestMapping("/cr-follow-up")
public @ResponseBody ResponseEntity<String> getData()
{
    restTemplate = new RestTemplate();
    httpHeaders = createHeadersWithAuthentication();
    httpHeaders.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON));
    HttpEntity<String> entity = new HttpEntity<String>(httpHeaders);
    ResponseEntity<String> response = restTemplate.exchange(jiraBaseURL, HttpMethod.GET, entity, String.class);

    return response;
}

Answer 1

尝试使用URLEncoder.encode() 编码您的网址