如何检查我的测试安卓设备是否连接到互联网？答案

【问题标题】：How to check My test android device is connected to internet or not?如何检查我的测试安卓设备是否连接到互联网？
【发布时间】：2015-09-08 05:40:47
【问题描述】：

protected boolean isOnline()            
{
      ConnectivityManager cm = (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);
      NetworkInfo info = cm.getActiveNetworkInfo();
      if (info != null && info.isConnectedOrConnecting()) {
        return true;
      }else
      {
        return  false;
      }
}
public void requestData()
{
    if (isOnline())
    {
        Toast.makeText(getApplicationContext(), "connected", Toast.LENGTH_LONG).show();
    }
    else
    {
        Toast.makeText(getApplicationContext(), "Niot Connected", Toast.LENGTH_LONG).show();
    }
}

我已经编写了这段代码，但我收到了类似“不幸的是您的程序已停止”之类的错误。请帮助我.. 提前致谢

【问题讨论】：

请在此处粘贴您的错误代码
Detect whether there is an Internet connection available on Android的可能重复

标签： android android-internet

【解决方案1】：

您需要将此添加到您的androidmanifest.xml

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

【讨论】：

【解决方案2】：

请检查此链接 http://www.androidhive.info/2012/07/android-detect-internet-connection-status/

Android Detect Internet Connection Status

的Demo

要访问互联网，我们需要 INTERNET 权限

要检测网络状态，我们需要 ACCESS_NETWORK_STATE 权限

【讨论】：

【解决方案3】：

调用这个方法

private boolean isNetworkAvailable() {
    ConnectivityManager connectivityManager 
          = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
    return activeNetworkInfo != null && activeNetworkInfo.isConnected();
}

并声明许可

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

【讨论】：

【解决方案4】：

这是适合我的代码。在你的 utils 中定义这个类。

    public class InternetConnection {

    public static boolean isNetworkAvailable(Context context) {
        ConnectivityManager connectivityManager
                = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo activeNetworkInfo = connectivityManager.getActiveNetworkInfo();
        return activeNetworkInfo != null;
    }
}

然后，在要检查连接状态的 Activity 中，使用，

if(!(InternetConnection.isNetworkAvailable(this))){
            internetActive = false;
            Toast.makeText(this, "Please try again with active Internet connection", Toast.LENGTH_LONG).show();
        }
        else {
// your code if device is connected to internet
}

确保你有

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

清单中的权限。

【讨论】：

【解决方案5】：

您将通过以下两种方法检查WIFI和移动数据是否连接：

public boolean checkWIFIInternetConn() {
        //Create object for ConnectivityManager class which returns network related info
        ConnectivityManager connectivity = (ConnectivityManager) _context.getSystemService(Context.CONNECTIVITY_SERVICE);
        //If connectivity object is not null
        if (connectivity != null) {
            //Get network info - WIFI internet access
            NetworkInfo info = connectivity.getNetworkInfo(ConnectivityManager.TYPE_WIFI);


            if (info != null) {
                //Look for whether device is currently connected to WIFI network
                if (info.isConnected()) {
                    return true;
                }
            }
        }
        return false;
    }

     public boolean checkMobileInternetConn() {
            //Create object for ConnectivityManager class which returns network related info
            ConnectivityManager connectivity = (ConnectivityManager) _context
                    .getSystemService(Context.CONNECTIVITY_SERVICE);
            //If connectivity object is not null
            if (connectivity != null) {
                //Get network info - Mobile internet access
                NetworkInfo info = connectivity.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);

                if (info != null) {
                    //Look for whether device is currently connected to Mobile internet
                    if (info.isConnected()) {
                        return true;
                    }
                }
            }
            return false;
        }

【讨论】：