如何将 stdClass 对象转换为参考数组？ (PHP)答案

【问题标题】：How to convert stdClass object in to refrence array? (PHP)如何将 stdClass 对象转换为参考数组？ (PHP)
【发布时间】：2014-07-10 17:42:37
【问题描述】：

我有变量 $related 女巫是 stdCalss 对象，我想用一个 foreach 循环将它转换为 reffrence 数组。

对象$related的Var_dump：

array (size=19)
  0 => 
    object(stdClass)[20]
      public 'id_product' => string '1568' (length=4)
      public 'related' => string '1567' (length=4)
  1 => 
    object(stdClass)[21]
      public 'id_product' => string '1568' (length=4)
      public 'related' => string '1562' (length=4)
  2 => 
    object(stdClass)[22]
      public 'id_product' => string '1568' (length=4)
      public 'related' => string '1564' (length=4)
  3 => 
    object(stdClass)[23]
      public 'id_product' => string '1568' (length=4)
      public 'related' => string '1410' (length=4)
  4 => 
    object(stdClass)[24]
      public 'id_product' => string '111' (length=3)
      public 'related' => string '77' (length=2)
  5 => 
    object(stdClass)[25]
      public 'id_product' => string '111' (length=3)
      public 'related' => string '1610' (length=4)

php代码：

     foreach ($related AS $r){
     ????
     }
     var_dump($rels);

希望的输出：

    $rels = array(
           '1568'=>'1567, 1562, 1564, 1410',
           '111'=>'77,1610'
            );

【问题讨论】：

标签： php arrays object reference

【解决方案1】：

构建一个临时数组并内爆它：

foreach($related AS $r) {
    $temp[$r->id_product][] = $r->related;
    $rels[$r->id_product]   = implode(', ', $temp[$r->id_product]);
}
print_r($rels);

【讨论】：

【解决方案2】：

$rels = array ();
foreach ($related as $r){
     $rels[$r->id_product] .= $r->related . ","; // put all of them with respective key together
}
$rels = array_map(
    function ($a) {
        $a = preg_replace('~,(?!.*,)~', '', $a);
        return $a;
    }
,$rels); // remove last commas
var_dump($rels);

【讨论】：

【解决方案3】：

试试，

$rels = array();
foreach($related as $r){

   $rels[$r->id_product] .= $r->related.', ';

}

array_walk_recursive($related, function(&$item){
    $item = rtrim($item,', ');
});

来自 PHP 文档：http://php.net/manual/en/language.types.type-juggling.php

【讨论】：