【问题标题】:Spring MVC POST submits are not workingSpring MVC POST 提交不起作用
【发布时间】:2015-03-06 10:44:52
【问题描述】:

我的应用服务器是 Weblogic 12C,它在 apache 代理后面工作。

当我通过 Spring MVC 表单进行 GET 提交时,值将进入后端,但是当我进行 POST 提交时,所有值在后端都为 null。

这是我的文件。

JSP 文件

    <form:form method="post" modelAttribute="userForm" action="createUser">

            <form:input path="userInfo.number" readonly="true" maxlength="100"/>
            <form:input path="userInfo.firstName" readonly="true" maxlength="500"/>
            <form:input path="userInfo.lastName" readonly="true" maxlength="500"/>
            <input type="submit" style="font-weight: bold;"                                             value="Send"></td>
</form:form>

控制器

@Controller
@RequestMapping(value = "/")
@SessionAttributes("user")
public class TestController {

@RequestMapping(method = RequestMethod.POST, value="createUser")
    public String createUser(@Valid UserForm userForm,BindingResult result,ModelMap modelMap) {
        LOGGER.debug("Handling POST description" + userForm.getFirstName());
}
}

web.xml

<web-app>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <listener> 
        <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
    </listener>

    <filter>
        <filter-name>characterEncodingFilter</filter-name>
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
        <init-param>
            <param-name>encoding</param-name>
            <param-value>UTF-8</param-value>
        </init-param>
        <init-param>
            <param-name>forceEncoding</param-name>
            <param-value>true</param-value>
        </init-param>
    </filter>

    <filter-mapping>
        <filter-name>characterEncodingFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <servlet>
        <servlet-name>userFormServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>
                /WEB-INF/spring-beans/servlet-context.xml
            </param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>userFormServlet</servlet-name>
        <url-pattern>/apps/*</url-pattern>
    </servlet-mapping>

【问题讨论】:

  • 试试这个网址 /apps/user/createUser 或 apps/user/createUser。

标签: java spring spring-mvc weblogic weblogic12c


【解决方案1】:

userForm.getFirstName() 这一行看来,似乎属性 firstNamelastNamenumber 是 userForm 对象,在这种情况下,您的表单应该是

<form:form method="post" modelAttribute="userForm" action="createUser">
            <form:input path="number" readonly="true" maxlength="100"/>
            <form:input path="firstName" readonly="true" maxlength="500"/>
            <form:input path="lastName" readonly="true" maxlength="500"/>
            <input type="submit" style="font-weight: bold;"                                             value="Send"></td>
</form:form>

根据您的 UserForm 类的结构,可能略有不同,但您应该从中了解解决方案的要点

【讨论】:

  • userForm 有另一个名为 User userInfo 的对象;并且 firstName、lastName 和数字映射到该对象。
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