【发布时间】:2018-03-05 21:49:49
【问题描述】:
我有以下数据集:
df <- data.frame(dens = rnorm(5000),
split = as.factor(sample(1:2, 5000, replace = T)),
method = as.factor(sample(c("A","B"), 5000, replace = T)),
counts = sample(c(1, 10, 100, 1000, 10000), 5000, replace = T))
我想要做的是为每个计数在 A 组和 B 组中的分裂 1 和 2 做分裂小提琴图(这将在对数刻度中,但这对于这个例子并不重要)。每个设置都有四个组,但它有一个嵌套的方面。
所以,我可以做到以下几点:
df$key <- factor(paste(df$split, df$method))
然后:
library(ggplot2)
ggplot(df, aes(x = factor(counts), y = dens, fill = split)) +
geom_violin(aes(fill = key), scale = "width", draw_quantiles = c(0.25, 0.5, 0.75)) + scale_fill_manual(values = cbPalette) + theme_bw()
但我真正想要的是浅蓝色和深蓝色作为分裂小提琴情节的两半,浅绿色和深绿色作为另一个小提琴分裂情节的两半,这些情节应该捆绑在一起一起。我也希望不同的计数彼此分开,但我觉得我可以解决这个问题。
请注意,这个问题与我列出的问题或Split violin plot with ggplot2 不同,因为我们为每个“计数”合并了两个不同级别的嵌套分割小提琴图。
我试图关注enter link description here 但是 我不知道如何将这样的嵌套组设置添加到那里的代码中,我正在寻找一些建议。
这是我尝试过的:
GeomSplitViolin <- ggproto("GeomSplitViolin", GeomViolin,
draw_group = function(self, data, ..., draw_quantiles = NULL){
# By @YAK: https://stackoverflow.com/questions/35717353/split-violin-plot-with-ggplot2
data <- transform(data, xminv = x - violinwidth * (x - xmin), xmaxv = x + violinwidth * (xmax - x))
grp <- data[1,'group']
newdata <- plyr::arrange(transform(data, x = if(grp%%2==1) xminv else xmaxv), if(grp%%2==1) y else -y)
newdata <- rbind(newdata[1, ], newdata, newdata[nrow(newdata), ], newdata[1, ])
newdata[c(1,nrow(newdata)-1,nrow(newdata)), 'x'] <- round(newdata[1, 'x'])
if (length(draw_quantiles) > 0 & !scales::zero_range(range(data$y))) {
stopifnot(all(draw_quantiles >= 0), all(draw_quantiles <= 1))
quantiles <- create_quantile_segment_frame(data, draw_quantiles, split = TRUE, grp = grp)
aesthetics <- data[rep(1, nrow(quantiles)), setdiff(names(data), c("x", "y")), drop = FALSE]
aesthetics$alpha <- rep(1, nrow(quantiles))
both <- cbind(quantiles, aesthetics)
quantile_grob <- GeomPath$draw_panel(both, ...)
ggplot2:::ggname("geom_split_violin", grid::grobTree(GeomPolygon$draw_panel(newdata, ...), quantile_grob))
}
else {
ggplot2:::ggname("geom_split_violin", GeomPolygon$draw_panel(newdata, ...))
}
}
)
create_quantile_segment_frame <- function (data, draw_quantiles, split = FALSE, grp = NULL) {
dens <- cumsum(data$density)/sum(data$density)
ecdf <- stats::approxfun(dens, data$y)
ys <- ecdf(draw_quantiles)
violin.xminvs <- (stats::approxfun(data$y, data$xminv))(ys)
violin.xmaxvs <- (stats::approxfun(data$y, data$xmaxv))(ys)
violin.xs <- (stats::approxfun(data$y, data$x))(ys)
if (grp %% 2 == 0) {
data.frame(x = ggplot2:::interleave(violin.xs, violin.xmaxvs),
y = rep(ys, each = 2), group = rep(ys, each = 2))
} else {
data.frame(x = ggplot2:::interleave(violin.xminvs, violin.xs),
y = rep(ys, each = 2), group = rep(ys, each = 2))
}
}
geom_split_violin <- function (mapping = NULL, data = NULL, stat = "ydensity", position = "identity", ..., draw_quantiles = NULL, trim = TRUE, scale = "area", na.rm = FALSE, show.legend = NA, inherit.aes = TRUE) {
layer(data = data, mapping = mapping, stat = stat, geom = GeomSplitViolin, position = position, show.legend = show.legend, inherit.aes = inherit.aes, params = list(trim = trim, scale = scale, draw_quantiles = draw_quantiles, na.rm = na.rm, ...))
}
library(ggplot2)
ggplot(df, aes(x = factor(counts), y = dens, fill = interaction(split,method))) +
geom_split_violin(draw_quantiles = c(0.25, 0.5, 0.75)) + scale_fill_manual(values=RColorBrewer::brewer.pal(name="Paired",n=4)) + theme_light() + theme(legend.position="bottom")
这是我得到的:
可以看出,绿色图像位于蓝色图像之上。我该如何解决这个问题?谢谢!
编辑:按照 Axeman 的建议,我快到了:
levels(df$split) <- factor(0:3)
library(ggplot2)
ggplot(df, aes(x = interaction(split, counts), y = dens, fill = key)) + geom_split_violin(draw_quantiles = c(0.25, 0.5, 0.75)) + scale_fill_manual(values=RColorBrewer::brewer.pal(name="Paired",n=4)) + theme_light() + theme(legend.position="bottom") + scale_x_discrete(interaction(df$split,df$counts)[-length(interaction(df$split,df$counts))], drop = FALSE)
快到了!
想要两个修复:拆分和计数之间的最后一次交互产生的空白,以及仅对每束计数的比例。 想知道这些是否应该是 Stackoverflow 上的单独问题。
快到了!
library(ggplot2)
ggplot(df, aes(x = interaction(split, counts), y = dens, fill = key)) + geom_split_violin(draw_quantiles = c(0.25, 0.5, 0.75)) +scale_fill_manual(values=RColorBrewer::brewer.pal(name="Paired",n=4)) + theme_light() + theme(legend.position="bottom") + scale_x_discrete(limits=levels(interaction(df$split,df$counts))[-length(levels(interaction(df$split,df$counts)))],drop = FALSE)
我仍然需要将计数值放在 x 轴上,在两个图之间。
【问题讨论】:
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我不清楚这里想要的输出是什么。
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抱歉,每次计数时,所需的输出将是两组分割小提琴图(A 或 B 内的 1 或 2 个),然后我们将沿着 x 轴上的计数进行。这有帮助吗?谢谢!
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添加了一个例子。希望现在事情变得更清楚了,但如果不是这样,请告诉我。
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我认为你能做的最好的就是
aes(x = interaction(split, counts), y = dens, fill = key)。