【发布时间】:2018-01-22 14:39:44
【问题描述】:
我试图使用 gremlin scala 使用 janusgraph 为 spark 设置 IntelliJ 构建,但我遇到了错误。
我的 build.sbt 文件是:
version := "1.0"
scalaVersion := "2.11.11"
libraryDependencies += "com.michaelpollmeier" % "gremlin-scala" % "2.3.0"
libraryDependencies += "org.apache.spark" %% "spark-core" % "2.2.1"
// https://mvnrepository.com/artifact/org.apache.spark/spark-sql
libraryDependencies += "org.apache.spark" %% "spark-sql" % "2.2.1"
// https://mvnrepository.com/artifact/org.apache.spark/spark-mllib
libraryDependencies += "org.apache.spark" %% "spark-mllib" % "2.2.1"
// https://mvnrepository.com/artifact/org.apache.spark/spark-hive
libraryDependencies += "org.apache.spark" %% "spark-hive" % "2.2.1"
// https://mvnrepository.com/artifact/org.janusgraph/janusgraph-core
libraryDependencies += "org.janusgraph" % "janusgraph-core" % "0.2.0"
libraryDependencies ++= Seq(
"ch.qos.logback" % "logback-classic" % "1.2.3" % Test,
"org.scalatest" %% "scalatest" % "3.0.3" % Test
)
resolvers ++= Seq(
Resolver.mavenLocal,
"Sonatype OSS" at "https://oss.sonatype.org/content/repositories/public"
)
但是当我尝试编译使用 gremlin scala 库或 io.Source 库的代码时出现错误。有人可以分享他们的构建文件或告诉我应该修改什么来修复它。 提前致谢。
所以,我试图编译这段代码:
import gremlin.scala._
import org.apache.commons.configuration.BaseConfiguration
import org.janusgraph.core.JanusGraphFactory
class Test1() {
val conf = new BaseConfiguration()
conf.setProperty("storage.backend", "inmemory")
val gr = JanusGraphFactory.open(conf)
val graph = gr.asScala()
graph.close
}
object Test{
def main(args: Array[String]) {
val t = new Test1()
println("in Main")
}
}
我得到的错误是:
错误:(1, 8) 未找到:对象 gremlin 导入 gremlin.scala._
Error:(10, 18) value asScala 不是 org.janusgraph.core.JanusGraph 的成员 val graph = gr.asScala()
【问题讨论】:
-
您能否至少提供您遇到的错误的文本?
-
我添加了错误文本。
标签: scala apache-spark gremlin janusgraph