【发布时间】:2014-06-19 14:15:24
【问题描述】:
我是第一次在项目中使用 log4j,我正在尝试使用自定义配置来输出日志。我希望记录器配置位于自定义文件中,而不是 log4j.xml 或 log4j.properties。这就是我现在拥有的:
构造函数:
public Manager(int managerID, String loggerConfigFile) {
this.MANAGER_ID = managerID;
logger = Logger.getLogger("testLogger" + MANAGER_ID);
PropertyConfigurator.configure(loggerConfigFile);
}
第一次调用logger的方法:
public void getPacketsFromStream(InputStream inputStream) {
logger.info("Manager " + MANAGER_ID + " started.");
(后面还有,不过不重要)
test1.config的内容(即构造函数中loggerConfigFile的值)
testLogger1=DEBUG,A1
log4j.appender.A1=org.apache.log4j.ConsoleAppender
log4j.appender.A1.layout=org.apache.log4j.PatternLayout
log4j.appender.A1.layout.ConversionPattern=%-4r %-5p [%t] %37c %3x - %m%n
我查过了,配置文件在类路径中。
我希望这会导致记录器将该语句写入控制台。相反,我得到(使用 -Dlog4j.debug 标志)以下输出:
log4j: Trying to find [log4j.xml] using context classloader sun.misc.Launcher$AppClassLoader@1f12c4e.
log4j: Trying to find [log4j.xml] using sun.misc.Launcher$AppClassLoader@1f12c4e class loader.
log4j: Trying to find [log4j.xml] using ClassLoader.getSystemResource().
log4j: Trying to find [log4j.properties] using context classloader sun.misc.Launcher$AppClassLoader@1f12c4e.
log4j: Trying to find [log4j.properties] using sun.misc.Launcher$AppClassLoader@1f12c4e class loader.
log4j: Trying to find [log4j.properties] using ClassLoader.getSystemResource().
log4j: Could not find resource: [null].
log4j: Could not find root logger information. Is this OK?
log4j: Finished configuring.
log4j:WARN No appenders could be found for logger (testLogger1).
log4j:WARN Please initialize the log4j system properly.
log4j:WARN See http://logging.apache.org/log4j/1.2/faq.html#noconfig for more info.
我做错了什么?
编辑:
我按照第一个答案的建议做了 - 之前移动了 log4j 配置并将 rootLogger 添加到配置文件log4j.rootLogger=DEBUG,A1,并得到了预期的输出。然后我尝试再修改一下配置文件,结果如下:
log4j.rootLogger=DEBUG,A0
testLogger1=DEBUG,A1
log4j.appender.A0=org.apache.log4j.ConsoleAppender
log4j.appender.A1=org.apache.log4j.ConsoleAppender
log4j.appender.A0.layout=org.apache.log4j.PatternLayout
log4j.appender.A1.layout=org.apache.log4j.PatternLayout
log4j.appender.A0.layout.ConversionPattern=%-4r %-5p [%t] %37c %3x --- %m%n
log4j.appender.A1.layout.ConversionPattern=%-4r %-5p [%t] %37c %3x - %m%n
请注意,A0 和 A1 的输出格式略有不同。 这是我在输出中得到的:
log4j: Trying to find [log4j.xml] using context classloader sun.misc.Launcher$AppClassLoader@1f12c4e.
log4j: Trying to find [log4j.xml] using sun.misc.Launcher$AppClassLoader@1f12c4e class loader.
log4j: Trying to find [log4j.xml] using ClassLoader.getSystemResource().
log4j: Trying to find [log4j.properties] using context classloader sun.misc.Launcher$AppClassLoader@1f12c4e.
log4j: Trying to find [log4j.properties] using sun.misc.Launcher$AppClassLoader@1f12c4e class loader.
log4j: Trying to find [log4j.properties] using ClassLoader.getSystemResource().
log4j: Could not find resource: [null].
log4j: Parsing for [root] with value=[DEBUG,A0].
log4j: Level token is [DEBUG].
log4j: Category root set to DEBUG
log4j: Parsing appender named "A0".
log4j: Parsing layout options for "A0".
log4j: Setting property [conversionPattern] to [%-4r %-5p [%t] %37c %3x --- %m%n].
log4j: End of parsing for "A0".
log4j: Parsed "A0" options.
log4j: Finished configuring.
0 INFO [main] testLogger1 --- Manager 1 started.
如何让 log4j 使用 testLogger1 及其附加程序 A1,而不是 rootLogger 和 A0?我本来希望getLogger("testLogger1") 这样做。
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