将变量作为 NSDict 从 Viewcontroller 传递到 Viewcontroller

Question

我有一个简单的注册故事板，询问用户他们的姓名等。我正在将输入的数据收集为 UITextfields，并希望将它们全部传递给最终的视图控制器，在那里我将其全部设为数组并将其发送到服务器。 JSON 但在添加测试数据时一切正常。

基础视图控制器

   struct NewUserStruct {
    var firstName: String
    var lastName: String
}

发送VC

let firstNameReg = inputFirstName.text
    let lastNameReg = inputLastName.text

    func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if let destVC = segue.destination as? RegistrationUpdateViewController {
            let newuser = NewUserStruct(firstName: firstNameReg! , lastName: lastNameReg! )
            print(newuser)
            destVC.newuser = newuser
        }        }

和接收VC

var newuser: NewUserStruct?
func createUser(){

guard let user = self.newuser else {
print("User is not set")
return
}

let service = "registration"
let parameters: [String: Any] = ["firstName": user.firstName,
                                 "lastName": user.lastName,
                                 "email": "Johnsmith@test11.com",
                                 "password": "12345678",
                                 "region": "EU",
                                 "bundleId":    Bundle.main.bundleIdentifier!,
                                 "appVersion": Bundle.main.infoDictionary?["CFBundleVersion"] as! String]

这可以编译，但我得到的 print(newuser) 值为 nil，它会打印保护 "User is not set"

这是我的整个 VC

import Foundation
import UIKit

class RegistrationNameViewController: BaseViewController {

@IBOutlet var inputFirstName: UITextField!
@IBOutlet var inputLastName: UITextField!



override func setup() {

}

override func navbarTitle() -> String {
    return "Name"
}

override func leftNavbarButtonType() -> NavbarButtonType {
    return NavbarButtonType.eNavbarButtonTypeBack
}

override func rightNavbarButtonType() -> NavbarButtonType {
    return NavbarButtonType.eNavbarButtonTypeNext

}

override func navbarViewNextPressed(_ navbarView: NavbarView) {
    let firstNameReg = inputFirstName.text
    let lastNameReg = inputLastName.text
    print(inputFirstName.text!,inputLastName.text!)

    func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if let destVC = segue.destination as? RegistrationUpdateViewController {
            print(destVC)
            let newuser = NewUserStruct(firstName: firstNameReg! , lastName: lastNameReg! )
            print(newuser)
            destVC.newuser = newuser
        }        }
    self.performSegue(withIdentifier: "NameToEmail", sender: nil)

}


override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

}

Answer 1

我会使用一个结构体，这样您就可以正确定义所传递的数据。

struct NewUser {
    var firstName: String
    var lastName: String
}

现在您可以创建此结构的实例并将其传递给prepare(for segue:) 中的目标视图控制器

override func navbarViewNextPressed(_ navbarView: NavbarView) {
    guard let firstName = inputFirstName.text where !firstName.isEmpty
          let lastName = inputLastName.text where !lastName.isEmpty else {
        print("first name and last name are required")
        return
    }

    let newUser = NewUser(firstName: firstName, lastName: lastName) 

    self.performSegue(withIdentifier: "NameToEmail", sender: newUser)
}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if let destVC = segue.destination as? RegistrationUpdateViewController {
        print(destVC)
        if let newuser = sender as? NewUser {  
            print(newuser)
            destVC.newuser = newuser
        }
    }
}

在您的目标视图控制器中：

class RegistrationUpdateViewController {
    var user: NewUser?

    func someFunction {
        guard let user = self.user else {
            print("User is not set")
            return
        }

        let service = "registration"
        let parameters: [String: Any] = ["firstName": user.firstName,
                                        "lastName": user.lastName,
                                        "email": "Johnsmith@test11.com",
                                        "password": "12345678",
                                        "region": "EU",
                                        "bundleId":    Bundle.main.bundleIdentifier!,
                                        "appVersion": Bundle.main.infoDictionary?["CFBundleVersion"] as! String] 
    ...
    }

}