【发布时间】:2019-05-11 02:46:43
【问题描述】:
类中有一行代码导致了问题。当我将其注释掉时,没有错误。我写的那行代码试图 grid() 一个 tk.Label。这在 Tkinter 中并没有什么特别之处,事实上在课堂上也没有什么特别之处。在尝试将此 tk.Label 网格化之前,我已经对许多其他 tk.Button(可变数量)进行了 grid() 错误显示:
_tkinter.TclError: cannot use geometry manager grid inside 。已经有由 pack 管理的 slave
如果我在该类中使用 pack,这将是有意义的,但我不是。
我已尝试删除和添加此行并从代码的其他部分取出包,但此错误仍然存在。
Board 类已从 board.py 导入到同一文件夹中的另一个文件中。这是工作代码,请不要太担心。
另外,请不要过多地谈论我的编码实践:
'''class MainPage(tk.Frame):
def __init__(self, parent, controller, rows):
tk.Frame.__init__(self,parent)
self.rows = rows.get()
self.board = Board(self.rows)
home_page_button = tk.Button(self, text = "Home", command = lambda: controller.show_frame(Home))
home_page_button.grid(row=11, column = 0, columnspan = 3)
self.board_of_buttons = []
self.ice_img = tk.PhotoImage(file="ice.gif")
self.boulder_img = tk.PhotoImage(file="boulder.gif")
for i in range(self.rows):
n = []
for j in range(self.rows):
n.append(tk.Button(self, image = self.ice_img, command = lambda x=i, y=j: self.change_mode(x,y,self.ice_img)))
self.board_of_buttons.append(n)
for i in range(self.rows):
for j in range(self.rows):
self.board_of_buttons[j][i].grid(row = i, column = j)
self.is_possible = tk.StringVar()
self.is_possible.set(self.get_is_possible())
self.is_possible_label = tk.Label(textvariable = self.is_possible)
self.is_possible_label.grid(row = self.rows + 1, column = 0, columnspan=self.rows) ###### <--- This is the line of code that causes the error. When I add it: error. When I take it away: Works
def change_mode(self,row,column,image):
self.change_image(row,column,image)
self.board.board[column][row].change_type()
def change_image(self, row, column, image):
if image == self.ice_img:
self.board_of_buttons[row][column] = tk.Button(self, image = self.boulder_img, command = lambda: self.change_mode(row,column,self.boulder_img))
self.board_of_buttons[row][column].grid(row = column, column = row)
else:
self.board_of_buttons[row][column] = tk.Button(self, image = self.ice_img, command = lambda: self.change_mode(row,column,self.ice_img))
self.board_of_buttons[row][column].grid(row = column, column = row)
def get_is_possible(self):
self.board.nodeify()
p = self.board.check_linkage()
self.board.switch_the_switches(p)
if self.board.is_possible():
return 'It is possible'
else:
return "It is not possible"
'''
感谢您的帮助
【问题讨论】:
标签: python python-3.x tkinter grid pack