Webview不断重新加载同一页面

Question

当点击网站内的链接时，如何防止我的以下代码重新加载同一页面？

protected void fetch_web(){
    WebView web;
    web = (WebView) findViewById(R.id.voice_mail_view_port);
    NoNetwork = (Button) findViewById(R.id.btn_no_internet);
    NoNetwork.setVisibility(View.GONE);
    String mdb = "http://192.168.23.1/default.php?appid=1.0";
    getWindow().setFeatureInt(  Window.FEATURE_PROGRESS, Window.PROGRESS_VISIBILITY_ON);
    final Activity MyActivity = this;
    web.setWebChromeClient(new WebChromeClient() {
        public void onProgressChanged(WebView view, int progress)
        {

            MyActivity.setTitle("Fetching feeds...");
            MyActivity.setProgress(progress * 100);

            loader();

            if(progress == 100) {
                MyActivity.setTitle(R.string.app_name);
                deLoader();;
            }
        }
    });
    web.setWebViewClient(new WebViewClient() {
        public void onReceivedError(WebView view, int errorCode, String description, String
                failingUrl) {
            deLoader();
            alert("No Internet Connection","Let's get connected to see feeds");
            //web.setVisibility(View.GONE);
            NoNetwork.setVisibility(View.VISIBLE);
        }
    });
    web.getSettings().setJavaScriptEnabled(true);
    web.loadUrl((mdb));
}
protected  void loader(){
    loading = (ProgressBar) findViewById(R.id.loader);
    loading.setVisibility(View.VISIBLE);
}
protected  void  deLoader(){
    loading = (ProgressBar) findViewById(R.id.loader);
    loading.setVisibility(View.INVISIBLE);
}
protected  void onStart(){
    fetch_web();
    super.onStart();
}

这是在我添加自定义错误message code时开始的

    web.setWebViewClient(new WebViewClient() {
        public void onReceivedError(WebView view, int errorCode, String description, String
                failingUrl) {
            deLoader();
            alert("No Internet Connection","Let's get connected to see feeds");
            //web.setVisibility(View.GONE);
            NoNetwork.setVisibility(View.VISIBLE);
        }
    });

我的期望是允许该应用在手机中安装的其他浏览器中打开链接或在同一个应用中打开它。

注意：webview上显示的所有链接都是下载链接

您看到的任何更改或添加的帮助，我只是 Java 新手，因此是我的第一个应用程序

Answer 1

试试这个代码：在你的new WebViewClient()里面

@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
    if (Uri.parse(url).getHost().equals("www.example.com")) {
        // This is your web site, so do not override; let WebView load the page
        return false;
    }
    // Otherwise, the link is not for a page on your site, so launch another Activity that handles URLs
    Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
    startActivity(intent);
    return true;
}

shouldOverrideUrlLoading参考

Answer 2

如果想在其他浏览器中打开链接。试试这个。

    Intent intent= new Intent(Intent.ACTION_VIEW,Uri.parse(your_web_url));
startActivity(intent);

希望这会有所帮助。:)

Answer 3

尝试上面的代码在您自己的应用程序中打开 url： xml文件：

<WebView
android:id="@+id/web_view"
android:layout_width="match_parent"
android:layout_height="match_parent"/>

java 文件：

private WebView webView;
webView = (WebView) findViewById(R.id.web_view);`
webView.getSettings().setJavaScriptEnabled(true);
webView.loadUrl("http://google.com");