mysql |分面搜索答案

【问题标题】：Mysql | Faceted searchmysql |分面搜索
【发布时间】：2014-09-15 08:37:42
【问题描述】：

我有一个小提琴：http://sqlfiddle.com/#!2/46a7b5/18

此请求返回所有属性。

|      META_NAME | META_VALUE | COUNT |
|----------------|------------|-------|
|       Car Type |      Coupe |     2 |
|       Car Type |      Sedan |     1 |
|          Color |      Black |     1 |
|          Color |        Red |     1 |
|          Color |      White |     1 |
| Interior Color |      Black |     2 |
| Interior Color |       Grey |     1 |
|           Make |        BMW |     2 |
|           Make |      Honda |     1 |
|          Model |    2Series |     1 |
|          Model |    3Series |     1 |
|          Model |      Civic |     1 |

要获得搜索结果，我有以下要求：

SELECT meta_name, meta_value, COUNT(DISTINCT item_id) count
  FROM meta m JOIN item_meta im
    ON im.field_id = m.id
 WHERE item_id IN
(
  SELECT i.id
  FROM item_meta im JOIN items i
    ON im.item_id = i.id JOIN meta m
    ON im.field_id = m.id
 GROUP BY i.id
HAVING MAX(meta_name = 'Make' AND meta_value = 'BMW') = 1
   AND MAX(meta_name = 'Car Type' AND meta_value = 'Coupe') = 1
)
 GROUP BY meta_name, meta_value;

And new fiddle.

我的输出：

|      META_NAME | META_VALUE | COUNT |
|----------------|------------|-------|
|       Car Type |      Coupe |     2 |
|          Color |      Black |     1 |
|          Color |      White |     1 |
| Interior Color |      Black |     1 |
| Interior Color |       Grey |     1 |
|           Make |        BMW |     2 |
|          Model |    2Series |     1 |
|          Model |    3Series |     1 |

我正在寻找获得如下结果的方法：

|      META_NAME | META_VALUE | COUNT |
|----------------|------------|-------|
|       Car Type |      Coupe |     2 |
|       Car Type |      Sedan |     0 |
|          Color |      Black |     1 |
|          Color |        Red |     0 |
|          Color |      White |     1 |
| Interior Color |      Black |     2 |
| Interior Color |       Grey |     1 |
|           Make |        BMW |     2 |
|           Make |      Honda |     0 |
|          Model |    2Series |     1 |
|          Model |    3Series |     1 |
|          Model |      Civic |     0 |

有可能吗？谢谢！

【问题讨论】：

标签： php mysql sql facet having

【解决方案1】：

您可以从左连接中获取值并计算不同的非空值，而不是使用子查询。

SELECT meta_name, meta_value, COUNT(DISTINCT pid) count
  FROM meta m JOIN item_meta im
    ON im.field_id = m.id
LEFT JOIN (
    SELECT i.id pid
  FROM item_meta im JOIN items i
    ON im.item_id = i.id JOIN meta m
    ON im.field_id = m.id
 GROUP BY i.id
HAVING MAX(meta_name = 'Make' AND meta_value = 'BMW') = 1
   AND MAX(meta_name = 'Car Type' AND meta_value = 'Coupe') = 1)
LJ ON im.item_id = LJ.pid
 GROUP BY meta_name, meta_value;

【讨论】：