如何在 C++ 游戏中设置失败条件？

Question

/我尝试在 C++ 上创建一个猜数游戏，我继续编写一个程序，生成一个从 1 到 1000 的随机数，并设置一个获胜条件。也就是说，如果用户输入随机生成的数字，那么他们就赢了。但我也想设置一个失败的条件。例如，用户在输掉游戏之前只有 10 次尝试。我有一种感觉，答案很简单，但我根本无法投入其中。\

#include <string>
#include <iostream>
#include <cstdlib>
#include <ctime>

using namespace std;

void tips()
{
    std::cout << "Pay attention to what the system inputs.\n";
    std::cout << "If Too High, Lower you're number base on your latest guess\n";
    std::cout << "If Too Low,  Guess a higher number base on your latest guess\n";
}

void help()
{
    std::cout << "The Instruction of the game is to guess the random generated number from one to a thousand\n";
}

void quit_game()
{
    std::cout << "You have quited the Game\n";
}

void play_game()
{
    int random = rand() % 1001; 
    std::cout << "Guess A Number:\n";
    while(true)
    {
        int guess;
          std::cin >> guess;
         if(guess == random)
        {
            std::cout << "You Are Victorous!\n";
            break;
        } else if (guess < random)
        {
            std::cout << "Too low\n";
        }else
        {
            std::cout << "Too high\n";
        }
    }
}

int main ()
{
  srand(time(NULL));
  int selected;
  do
    {
     std::cout << "0. Quit Game" << std::endl << "1. Play Game\n";
     std::cout << "2. Help" << std::endl << "3. Tips\n";
     std::cin >> selected;

       switch (selected)
       {
        case 0:
           quit_game();
             break;
        case 1:
           play_game();
             break;
        case 2:
           help();
             break;
        case 3:
           tips();
            break;
       
       default:
           std::cout << "You have entered an invalid option\n";
       }
    }

  while (selected != 0);
}

Answer 1

您可以使用 for 循环来代替 while(true)：

#include <string>
#include <iostream>
#include <cstdlib>
#include <ctime>

using namespace std;

void tips()
{
    std::cout << "Pay attention to what the system inputs.\n";
    std::cout << "If Too High, Lower you're number base on your latest guess\n";
    std::cout << "If Too Low,  Guess a higher number base on your latest guess\n";
}

void help()
{
    std::cout << "The Instruction of the game is to guess the random generated number from one to a thousand\n";
}

void quit_game()
{
    std::cout << "You have quited the Game\n";
}

void play_game(std::size_t max_guesses)
{
    int random = rand() % 1001; 
    std::cout << "Guess A Number:\n";
    for(std::size_t i=0;i<max_guesses;++i)
    {
        int guess;
          std::cin >> guess;
        if(guess == random)
        {
            std::cout << "You Are Victorous!\n";
            return;
        } else if (guess < random)
        {
            std::cout << "Too low\n";
        }else
        {
            std::cout << "Too high\n";
        }
    }

    std::cout << "You Lost!\n";
    return;
}

int main ()
{
  srand(time(NULL));
  constexpr std::size_t num_guesses=5;
  int selected;
  do
    {
     std::cout << "0. Quit Game" << std::endl << "1. Play Game\n";
     std::cout << "2. Help" << std::endl << "3. Tips\n";
     std::cin >> selected;

       switch (selected)
       {
        case 0:
           quit_game();
             break;
        case 1:
            play_game(num_guesses);
             break;
        case 2:
           help();
             break;
        case 3:
           tips();
            break;
       
       default:
           std::cout << "You have entered an invalid option\n";
       }
    }

  while (selected != 0);
}

Answer 2

您可以在 play_game 函数中使用另一个变量来跟踪玩家的尝试次数。

void play_game()
{
    static const int MAX_GUESSES = 10; // You can change this
    int number_of_guesses = 0;

    int random = rand() % 1001; 
    std::cout << "Guess A Number:\n";
    while(true)
    {
        int guess;
          std::cin >> guess;
         if(guess == random)
        {
            std::cout << "You Are Victorous!\n";
            break;
        } else if (guess < random)
        {
            std::cout << "Too low\n";
        }else
        {
            std::cout << "Too high\n";
        }

        ++number_of_guesses;
        if (number_of_guesses == MAX_GUESSES)
        {
            std::cerr << "Too many guesses!" << std::endl;
            break;
        }
    }
}

Answer 3

您需要使用一个全局变量作为最大尝试次数，并使用另一个变量来计算用户播放次数。

const unsigned Maximum_try = 10;

void play_game()
{
    static unsigned number_of_play = 0;
    int random = rand() % 1001;
    std::cout << "Guess A Number:\n";
    while (true)
    {
        int guess;
        std::cin >> guess;
        number_of_play++;
        if (guess == random)
        {
            std::cout << "You Are Victorous!\n";
            break;
        }
        else if (guess < random)
        {
            std::cout << "Too low\n";
        }
        else
        {
            std::cout << "Too high\n";
        }

        if (number_of_play == Maximum_try)
        {
            std::cout << "The answer was: " << random << std::endl;
            std::cout << "YOU LOSE! Try again dear :-)\n";
            number_of_play = 0; 
            break;
        }
    }
}