【发布时间】:2011-12-18 12:42:08
【问题描述】:
我想知道为什么我的更新没有填充本地 Sqlite 数据库。昨天数据库应用程序中很少有记录正常工作。今天在插入另外 10 条记录后。两种发送方法似乎都可以正常工作,但它们不返回数据。它只更新 IngredientDB 而不是 RecipeID Request 。这是我的更新动作脚本代码,
dishName.addEventListener("Success", dishName_resultHandler);
dishName.addEventListener("...", faultHandler);
dishName.send();
dishIngs.addEventListener("Success", ingredients_resultHandler);
dishIngs.addEventListener("...", faultHandler);
dishIngs.send();
protected function dishName_resultHandler(event:ResultEvent):void
{
externalRecipes=event.result.recipes.recipe;
}
protected function ingredients_resultHandler(event:ResultEvent):void{
externalIngredients=event.result.ingredients.ingredient;
}
这是我的第一个表的 php 脚本
$mysql_host = "...";
$mysql_database = "...";
$mysql_user = "...";
$mysql_password = "....";
$conn = mysql_connect("...", "...","...") or die(mysql_error());
mysql_select_db("....", $conn);
$sql = 'SELECT * FROM `RecipeDB`';
$res = mysql_query($sql);
$xml = new XMLWriter();
$xml->openURI("php://output");
$xml->startDocument();
$xml->setIndent(true);
$xml->startElement('recipes');
while ($row = mysql_fetch_assoc($res)) {
$xml->startElement("recipe");
$xml->writeElement('RecipeID', $row['RecipeID']);
$xml->writeElement('Name', $row['Name']);
$xml->writeElement('Category', $row['Category']);
$xml->writeElement('Origin', $row['Origin']);
$xml->writeElement('Recipe', $row['Recipe']);
$xml->writeElement('Favorite', $row['Favorite']);
$xml->writeElement('Image', base64_encode($row['Image']));
$xml->endElement();
}
$xml->endElement();
$xml->flush();
第二个类似
$conn = mysql_connect("...", "..","...") or die(mysql_error());
mysql_select_db("....", $conn);
$sql = 'SELECT * FROM `IngredientDB`';
$res = mysql_query($sql);
$xml = new XMLWriter();
$xml->openURI("php://output");
$xml->startDocument();
$xml->setIndent(true);
$xml->writeRaw('<?xml version="1.0"?>');
$xml->startElement('ingredients');
while ($row = mysql_fetch_assoc($res)) {
$xml->startElement("ingredient");
$xml->writeElement('rowid', $row['rowid']);
$xml->writeElement('RecipeID', $row['RecipeID']);
$xml->writeElement('Ingredient', $row['Ingredient']);
$xml->writeElement('Quantity', $row['Quantity']);
$xml->endElement();
}
这是我对服务器的调用
<s:HTTPService id="dishName"
url="http://.../dish.php"
result="dishName_resultHandler(event)"
fault="faultHandler(event)"/>
<s:HTTPService id="dishIngs"
url="http://.../Ingedient.php"
result="ingredients_resultHandler(event)"
fault="faultHandler(event)"/>
这是我的数据库结构
CREATE TABLE `RecipeDB` (
`RecipeID` int(5) NOT NULL AUTO_INCREMENT,
`Name` varchar(20) COLLATE latin1_general_ci NOT NULL,
`Category` varchar(20) COLLATE latin1_general_ci NOT NULL,
`Origin` varchar(20) COLLATE latin1_general_ci NOT NULL,
`Recipe` varchar(2000) COLLATE latin1_general_ci NOT NULL,
`Favorite` tinyint(1) NOT NULL,
`Image` blob NOT NULL,
PRIMARY KEY (`RecipeID`)
)
CREATE TABLE `IngredientDB` (
`rowid` int(5) NOT NULL AUTO_INCREMENT,
`RecipeID` int(5) NOT NULL,
`Ingredient` varchar(20) COLLATE latin1_general_ci NOT NULL,
`Quantity` varchar(100) COLLATE latin1_general_ci NOT NULL,
PRIMARY KEY (`rowid`)
)
【问题讨论】:
-
那么是sqlite还是mysql? “不返回任何值”到底是什么意思?
-
您的虚拟主机似乎将谷歌分析代码添加到 php 输出。您使用 Flash 内容调试器插件吗?它是否抱怨格式错误的 XML?
-
顺便说一句。您应该真的从代码示例中删除数据库详细信息...
-
数据库是mysql。并且不返回任何值,这意味着没有为 externalRecipes 和 externalIngredients arrayCollection 分配任何值(顺便说一下它们都是预先初始化的)没有显示错误
标签: php mysql actionscript-3 apache-flex flex4.5