如何计算日期范围是否在本周内[关闭]

Question

我使用返回以下数据的 API：

{
"count": 3,
"data": [
    {
        "id": "11ec62fcfc82e511b06a756430fa6a9e",
        "type": "HOLIDAY",
        "from": "2021-12-13",
        "to": "2021-12-19",
        "resourceId": "11ec46d6abeeeb08b8f937e6be68fdf0",
        "createdAt": "2021-12-22T07:58:44"
    },
    {
        "id": "11ec5e81746041328bd6f1d234a6c496",
        "type": "ILLNESS",
        "from": "2021-12-15",
        "to": "2021-12-17",
        "resourceId": "11ec46e7a62ab8f6b8f937e6be68fdf0",
        "createdAt": "2021-12-16T03:04:23"
    },
    {
        "id": "11ec62ff1df2654d8bd6f1d234a6c496",
        "type": "HOLIDAY",
        "from": "2021-12-24",
        "to": "2021-12-24",
        "resourceId": "11ec46d6547a00728be3e1ed8ff29535",
        "createdAt": "2021-12-22T08:14:00"
    }
],
"success": true
}

这些是假期和疾病数据。我有一份每周报告，我需要计算特定“ressourceID”在该周内休假/生病的天数。如何计算特定周内“从”-“到”范围内的天数？

我不知道如何轻松做到这一点。我在考虑 https://www.php.net/manual/de/datetime.format.php 将其转换为“z”格式，但我也找不到简单的方法。

让我添加一个我正在寻找的示例，我认为这个问题并不清楚：

假设我们有下一周：

考虑周：20.12。 - 24.12.

现在我们可以有以下缺勤情况以及如何考虑这些情况

案例 1：缺勤在 Weekstart 之前开始并在一周内结束

缺席：15.12。 - 21.12.

=> 在这种情况下，一周中包含 2 天

案例 2：缺勤在 Weekstart 之前开始并在一周之后结束

缺席：15.12。 - 26.12.

=> 在这种情况下，一周中包含 5 天

案例 3：缺勤在一周内开始，在一周内结束

缺席 = 20.12。 - 22.12.

=> 在这种情况下，一周中包含 3 天

案例 4：缺勤始于一周内，一周后结束

缺席：21.12。 - 29.12.

=> 在这种情况下，一周中包含 4 天

一般来说，我正在寻找一种方法来比较 2 个日期范围（周和缺席）并获取两个范围之间的交集天数。 In Chinese: 我这周有多少天的假期/病假。

Answer 1

以下代码将根据 FROM DATE & TO DATE GIVEN 给出周数。

$from = new \DateTime('2020-12-15');
$to = new \DateTime('2020-12-17');
$weeks = date_diff($to,$from)->days/7;

如果结果为 0 则为第一周。

或者，如果您想获取基于 FROM DATE 到 CURRENT DATE 的周数。

$from = new \DateTime('2020-12-15');
$to = new \DateTime();
$weeks = date_diff($to,$from)->days/7;

Answer 2

这将遍历数组并检查日期是否在本周创建。

// This is the json string that was returned
$jsonString = '{"count":3,"data":[{"id":"11ec62fcfc82e511b06a756430fa6a9e","type":"HOLIDAY","from":"2021-12-13","to":"2021-12-19","resourceId":"11ec46d6abeeeb08b8f937e6be68fdf0","createdAt":"2021-12-22T07:58:44"},{"id":"11ec5e81746041328bd6f1d234a6c496","type":"ILLNESS","from":"2021-12-15","to":"2021-12-17","resourceId":"11ec46e7a62ab8f6b8f937e6be68fdf0","createdAt":"2021-12-16T03:04:23"},{"id":"11ec62ff1df2654d8bd6f1d234a6c496","type":"HOLIDAY","from":"2021-12-24","to":"2021-12-24","resourceId":"11ec46d6547a00728be3e1ed8ff29535","createdAt":"2021-12-22T08:14:00"}],"success":true}';

// This will decode the json string make an array
$data = json_decode($jsonString, true);

// Function to check date was created this week
function checkWeek($date) {
    // will get current date and - 7 days
    $ThisWeek = time() - (7 * 24 * 60 * 60);
    
    // will change from date from string to timestamp
    $DateCreated = strtotime($date);
    
    // will check if the createdDate > this week
    if($DateCreated >= $ThisWeek) {
        echo $date . ", Was Created This Week.\n";
        return true;
    }
    return false;
}

// Loop through all values and check which one is created this week
foreach ($data["data"] as &$value) {
    checkWeek($value["createdAt"]);
}