【发布时间】:2016-07-25 08:14:31
【问题描述】:
首先:我找到了这个topic,但它不起作用。
我有两个模型之间的关系
Council(1)<->(n)Department
我想插入一个与部门没有关系的委员会。
我有这个 ecto 架构:
schema "councils" do
field :name, :string
field :description, :string
belongs_to :department, Db2.Department
many_to_many :students, Db2.Student, join_through: Db2.StudentCouncil
many_to_many :periods, Db2.Period, join_through: Db2.StudentCouncil
timestamps()
end
使用此 SQL 架构:
CREATE TABLE public.councils
(
id integer NOT NULL DEFAULT nextval('councils_id_seq'::regclass),
name character varying(255),
description character varying(255),
department_id integer,
inserted_at timestamp without time zone NOT NULL,
updated_at timestamp without time zone NOT NULL,
CONSTRAINT councils_pkey PRIMARY KEY (id),
CONSTRAINT councils_department_id_fkey FOREIGN KEY (department_id)
REFERENCES public.departments (id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
)
文档说 cast/4 已弃用,但 phoenix 自己创建了带有 cast/3 和 validate_required/3 的变更集。我只添加了department,所以我有以下变更集:
def changeset(struct, params \\ %{}) do
struct
|> cast(params, [:name, :description, :department_id])
|> validate_required([:name])
|> unique_constraint(:name)
|> assoc_constraint(:department)
end
对于表单,我使用默认的 phoenix.html 表单元素。 当我提交表单时,凤凰说:
[debug] QUERY OK db=1.2ms queue=0.1ms
SELECT u0."id", u0."uid", u0."is_admin", u0."is_staff", u0."password_hash", u0."inserted_at", u0."updated_at" FROM "users" AS u0 WHERE (u0."id" = $1) [1]
[debug] Processing by Db2.CouncilController.create/2
Parameters: %{"_csrf_token" => "KwpdFCZ/bFN9fwkcXSAYLhRCIzgOAAAAXeoEa4+d1MoT7SvzZpgOdg==", "_utf8" => "✓", "council" => %{"department_id" => "", "description" => "", "name" => "test2"}}
Pipelines: [:browser]
[debug] QUERY OK db=1.2ms queue=0.1ms
#Ecto.Changeset<action: :insert, changes: %{description: "", name: "test2"},
errors: [department_id: {"is invalid", [type: :id]}], data: #Db2.Council<>,
valid?: false>
【问题讨论】:
标签: elixir phoenix-framework ecto