通过附加在函数中更新实例变量...不起作用？

Question

我将尝试先在此处添加所有相关代码，然后再解释我的问题。更多的是 python 的新手，只是想做一个我觉得对我有挑战性的项目，所以我想做一些有点像“然后没有”、线索和我们中间的事情，如果那样的话有助于上下文。

功能 1 - 随机确定角色将移动到哪个房间，更新所有玩家房间信息，并将该角色添加到房间实例中的角色列表中。这似乎是问题所在？

#room_options is list of rooms that depends on what room char is currently in. Passed in from instance object.

all_rooms = [hallway, kitchen, living_room]
def set_next_room(room_options):
    completed_chars = []
    for room in all_rooms:
        characters_in_room = room.get_occupants()
        characters_in_room = characters_in_room[:]
        #empties room so new characters can be assigned to room
        room.characters.clear()
        #if the person in characters in room is in completed characters, take them out of the characters in room list that will be run in next for loop
        for char in characters_in_room[:]:
            if char in completed_chars:
                characters_in_room.remove(char)
        #sets new rooms for each character in each room
        for char in characters_in_room:
            rand_int = randint(0, len(room_options)-1)
            rand_room = room_options[rand_int]
            #sets next room based on available choices
            char.set_next_room(rand_room)
            #adds character to the next room character list
            next_room = function_mapping_rooms(char.get_next_room())
            next_room.characters.append(char) #this line is not working??
            #changes rooms from current to previous, next to current, and next to None
            char.set_prev_room(char.get_current_room)
            char.set_current_room(next_room.name)
            char.set_next_room(None)

            #adds person to the completed list so room determination is not duplicated
            completed_chars.append(char)

函数 2 - 对问题不是特别重要，但包含在内是因为上面调用了此函数...更多上下文

def function_mapping_rooms(room_name):
    characters = {
        'hallway': hallway,
        'kitchen': kitchen,
        'living room': living_room,
        'player death': player_death,
        'accusation': accusation
    }
    return characters.get(room_name)

房间的基本示例类

class Kitchen:
    def __init__(self, name, weapon, characters):
        self.name = name
        self.weapon = weapon
        self.characters = characters
        self.room_options = ['hallway', 'living room']
    
   def enter(self):
        set_next_room(self.room_options)


kitchen = Kitchen('kitchen', 'kitchen knife', [])

所以问题是这样的。根据我对代码的理解，第一个代码块中的next_room.characters.append(char) 行应该是在“厨房”类的实例中添加一个从characters_in_room 到self.characters 的字符。当我通过调试器运行代码时，房间的字符列表会更新。但是，一旦 set_next_room 函数完成并且我想使用新更新的字符列表，列表 self.characters 就会显示为空。有人对为什么会这样有任何建议吗？我猜它与记忆和存储有关？

提前致谢。

Answer 1

原来答案是错误的逻辑。我使函数比我需要的复杂得多。请参阅下面的更正代码。

def set_next_room(room_options):
    completed_chars = []
    for room in all_rooms:
        characters_in_room = room.get_occupants()
        for char in characters_in_room[:]:
            if char in completed_chars:
                continue
            #determines random room from available choices and sets equal to character's next room
            rand_int = randint(0, len(room_options)-1)
            rand_room = room_options[rand_int]
            char.set_next_room(rand_room)

            #gets the objects for current and next rooms to enable instance character list manipulation
            current_room = function_mapping_rooms(char.get_current_room())
            next_room = function_mapping_rooms(char.get_next_room())
            print(next_room.name)
            next_room.characters.append(char)
            current_room.characters.remove(char)

            #changes character rooms from current to previous, next to current, and next to None
            char.set_prev_room(char.get_current_room)
            char.set_current_room(next_room)
            char.set_next_room(None)

            #adds character to completed list so room determination is not duplicated
            completed_chars.append(char)